0:00:00.000,0:00:00.550 0:00:00.550,0:00:03.240 I think it's pretty common[br]knowledge how to find the area 0:00:03.240,0:00:06.030 of the triangle if we know the[br]length of its base 0:00:06.030,0:00:07.250 and its height. 0:00:07.250,0:00:10.540 So, for example, if that's my[br]triangle, and this length right 0:00:10.540,0:00:14.910 here-- this base-- is of length[br]b and the height right here is 0:00:14.910,0:00:19.080 of length h, it's pretty common[br]knowledge that the area of this 0:00:19.080,0:00:23.170 triangle is going to be equal[br]to 1/2 times the base 0:00:23.170,0:00:24.440 times the height. 0:00:24.440,0:00:30.240 So, for example, if the base[br]was equal to 5 and the height 0:00:30.240,0:00:37.180 was equal to 6, then our area[br]would be 1/2 times 5 times 6, 0:00:37.180,0:00:41.770 which is 1/2 times 30--[br]which is equal to 15. 0:00:41.770,0:00:45.120 Now what is less well-known is[br]how to figure out the area of a 0:00:45.120,0:00:48.250 triangle when you're only given[br]the sides of the triangle. 0:00:48.250,0:00:49.740 When you aren't[br]given the height. 0:00:49.740,0:00:53.470 So, for example, how do[br]you figure out a triangle 0:00:53.470,0:00:55.570 where I just give you the[br]lengths of the sides. 0:00:55.570,0:01:00.530 Let's say that's side a, side[br]b, and side c. a, b, and c are 0:01:00.530,0:01:01.640 the lengths of these sides. 0:01:01.640,0:01:03.360 How do you figure that out? 0:01:03.360,0:01:05.270 And to do that we're[br]going to apply something 0:01:05.270,0:01:06.430 called Heron's Formula. 0:01:06.430,0:01:12.210 0:01:12.210,0:01:13.790 And I'm not going to[br]prove it in this video. 0:01:13.790,0:01:15.200 I'm going to prove it[br]in a future video. 0:01:15.200,0:01:17.400 And really to prove it you[br]already probably have 0:01:17.400,0:01:18.720 the tools necessary. 0:01:18.720,0:01:20.480 It's really just the[br]Pythagorean theorem and 0:01:20.480,0:01:22.220 a lot of hairy algebra. 0:01:22.220,0:01:24.230 But I'm just going to show you[br]the formula now and how to 0:01:24.230,0:01:26.760 apply it, and then you'll[br]hopefully appreciate that it's 0:01:26.760,0:01:28.590 pretty simple and pretty[br]easy to remember. 0:01:28.590,0:01:31.660 And it can be a nice trick[br]to impress people with. 0:01:31.660,0:01:36.320 So Heron's Formula says first[br]figure out this third variable 0:01:36.320,0:01:38.640 S, which is essentially[br]the perimeter of this 0:01:38.640,0:01:40.660 triangle divided by 2. 0:01:40.660,0:01:45.810 a plus b plus c, divided by 2. 0:01:45.810,0:01:49.480 Then once you figure out S, the[br]area of your triangle-- of this 0:01:49.480,0:01:55.840 triangle right there-- is going[br]to be equal to the square root 0:01:55.840,0:01:59.710 of S-- this variable S right[br]here that you just calculated-- 0:01:59.710,0:02:10.540 times S minus a, times S[br]minus b, times S minus c. 0:02:10.540,0:02:12.480 That's Heron's[br]Formula right there. 0:02:12.480,0:02:13.830 This combination. 0:02:13.830,0:02:16.130 Let me square it off for you. 0:02:16.130,0:02:18.700 So that right there[br]is Heron's Formula. 0:02:18.700,0:02:21.610 And if that looks a little bit[br]daunting-- it is a little bit 0:02:21.610,0:02:24.290 more daunting, clearly, than[br]just 1/2 times base 0:02:24.290,0:02:25.290 times height. 0:02:25.290,0:02:28.040 Let's do it with an actual[br]example or two, and actually 0:02:28.040,0:02:31.350 see this is actually[br]not so bad. 0:02:31.350,0:02:33.320 So let's say I have a triangle. 0:02:33.320,0:02:35.300 I'll leave the[br]formula up there. 0:02:35.300,0:02:37.460 So let's say I have a[br]triangle that has sides 0:02:37.460,0:02:44.920 of length 9, 11, and 16. 0:02:44.920,0:02:47.040 So let's apply Heron's Formula. 0:02:47.040,0:02:51.190 S in this situation is going to[br]be the perimeter divided by 2. 0:02:51.190,0:02:56.630 So 9 plus 11 plus[br]16, divided by 2. 0:02:56.630,0:03:00.430 Which is equal to 9 plus[br]11-- is 20-- plus 16 is 0:03:00.430,0:03:04.660 36, divided by 2 is 18. 0:03:04.660,0:03:09.430 And then the area by Heron's[br]Formula is going to be equal to 0:03:09.430,0:03:19.380 the square root of S-- 18--[br]times S minus a-- S minus 9. 0:03:19.380,0:03:27.790 18 minus 9, times 18 minus[br]11, times 18 minus 16. 0:03:27.790,0:03:31.490 0:03:31.490,0:03:38.200 And then this is equal to[br]the square root of 18 0:03:38.200,0:03:44.730 times 9 times 7 times 2. 0:03:44.730,0:03:47.340 Which is equal to-- let's[br]see, 2 times 18 is 36. 0:03:47.340,0:03:48.900 So I'll just[br]rearrange it a bit. 0:03:48.900,0:03:56.700 This is equal to the square[br]root of 36 times 9 times 7, 0:03:56.700,0:04:05.540 which is equal to the square[br]root of 36 times the square 0:04:05.540,0:04:09.330 root of 9 times the[br]square root of 7. 0:04:09.330,0:04:14.130 The square root[br]of 36 is just 6. 0:04:14.130,0:04:16.040 This is just 3. 0:04:16.040,0:04:17.750 And we don't deal with the[br]negative square roots, 0:04:17.750,0:04:19.920 because you can't have[br]negative side lengths. 0:04:19.920,0:04:23.460 And so this is going to[br]be equal to 18 times 0:04:23.460,0:04:26.120 the square root of 7. 0:04:26.120,0:04:28.060 So just like that, you saw it,[br]it only took a couple of 0:04:28.060,0:04:30.760 minutes to apply Heron's[br]Formula, or even less than 0:04:30.760,0:04:33.420 that, to figure out that the[br]area of this triangle 0:04:33.420,0:04:38.710 right here is equal to 18[br]square root of seven. 0:04:38.710,0:04:42.040 Anyway, hopefully you[br]found that pretty neat. 0:04:42.040,0:04:42.331