1 00:00:00,990 --> 00:00:04,056 The expression 5X 2 00:00:04,056 --> 00:00:10,970 minus 4. Greater than two X plus 3 looks like an 3 00:00:10,970 --> 00:00:15,670 equation, but with the equal sign replaced by an Arrowhead. 4 00:00:16,990 --> 00:00:19,138 This denotes that the. 5 00:00:19,720 --> 00:00:24,760 Part on the left, 5X minus four is greater than the part on the 6 00:00:24,760 --> 00:00:26,200 right 2X plus 3. 7 00:00:27,440 --> 00:00:29,911 We use four symbols to denote in 8 00:00:29,911 --> 00:00:34,358 Equalities. This symbol means is greater than. 9 00:00:36,840 --> 00:00:41,043 This symbol means is greater than or equal to. 10 00:00:42,140 --> 00:00:44,966 This symbol means is less than. 11 00:00:45,890 --> 00:00:50,180 On this symbol means is less than or equal to. 12 00:00:51,380 --> 00:00:55,516 Notice that the Arrowhead always points to the 13 00:00:55,516 --> 00:00:56,550 smaller expression. 14 00:00:58,780 --> 00:01:01,580 In Equalities can be manipulated like equations 15 00:01:01,580 --> 00:01:03,580 and follow very similar rules. 16 00:01:04,940 --> 00:01:06,998 But there is one important exception. 17 00:01:08,790 --> 00:01:13,925 If you add the same number to both sides of an inequality, the 18 00:01:13,925 --> 00:01:17,875 inequality remains true. If you subtract the same number from 19 00:01:17,875 --> 00:01:22,615 both sides of the inequality, it remains true. If you multiply or 20 00:01:22,615 --> 00:01:26,565 divide both sides of an inequality by the same positive 21 00:01:26,565 --> 00:01:28,145 number, it remains true. 22 00:01:29,860 --> 00:01:33,955 But if you multiply or divide both sides of an inequality by a 23 00:01:33,955 --> 00:01:36,000 negative number. It's no longer 24 00:01:36,000 --> 00:01:40,217 true. In fact, the inequality becomes reversed. This is quite 25 00:01:40,217 --> 00:01:45,066 easy to see because we can write that four is greater than two. 26 00:01:45,860 --> 00:01:50,800 But if we multiply both sides of this inequality by minus one, we 27 00:01:50,800 --> 00:01:51,940 get minus 4. 28 00:01:52,440 --> 00:01:54,990 Is less than minus 2? 29 00:01:55,710 --> 00:01:57,786 We have to reverse the inequality. 30 00:01:58,920 --> 00:02:05,336 This leads to difficulties when dealing with variables 31 00:02:05,336 --> 00:02:11,752 because of variable can be either positive or 32 00:02:11,752 --> 00:02:14,704 negative. Look at these two 33 00:02:14,704 --> 00:02:17,244 inequalities. X is greater than 34 00:02:17,244 --> 00:02:19,710 one. And X squared. 35 00:02:20,230 --> 00:02:21,650 Is greater than X. 36 00:02:23,380 --> 00:02:27,566 Now clearly if X squared is greater than ex, ex can't be 0. 37 00:02:28,280 --> 00:02:31,880 So it looks as if we ought to be able to divide both sides of 38 00:02:31,880 --> 00:02:34,230 this inequality by X. Giving us. 39 00:02:34,740 --> 00:02:38,088 X greater than one, which is what we've got on the left. 40 00:02:39,750 --> 00:02:43,134 But in fact we can't do this. These two inequalities are not 41 00:02:43,134 --> 00:02:47,100 the same. This is because X can be negative. 42 00:02:48,440 --> 00:02:53,055 Here we're saying that X is greater than one, so X must be 43 00:02:53,055 --> 00:02:56,280 positive. But here we have to take into account the 44 00:02:56,280 --> 00:02:57,580 possibility that X is negative. 45 00:02:58,180 --> 00:03:04,600 In fact, the complete solution for this is X is greater than 46 00:03:04,600 --> 00:03:07,810 one or X less than 0. 47 00:03:08,420 --> 00:03:11,450 Because obviously if X is negative, then X squared is 48 00:03:11,450 --> 00:03:15,389 always going to be greater than X. I'll show you exactly how to 49 00:03:15,389 --> 00:03:18,419 get the solution for this type of inequality later on. 50 00:03:20,930 --> 00:03:23,930 Great care really has to be taken when solving inequalities 51 00:03:23,930 --> 00:03:27,530 to make sure that you don't multiply or divide by a negative 52 00:03:27,530 --> 00:03:33,157 number by accident. For example, saying that X is greater than Y. 53 00:03:34,140 --> 00:03:40,954 Implies. That X squared is greater than Y 54 00:03:40,954 --> 00:03:44,064 squared only if X&Y are 55 00:03:44,064 --> 00:03:51,126 positive. I'll start with a very simple 56 00:03:51,126 --> 00:03:57,958 inequality. X +3 is greater than two. 57 00:03:59,040 --> 00:04:03,048 To solve this, we simply need to subtract 3 from both sides. 58 00:04:03,048 --> 00:04:07,724 If we subtract 3 from the left hand side were left with X. If 59 00:04:07,724 --> 00:04:11,732 we subtract 3 from the right hand side were left with minus 60 00:04:11,732 --> 00:04:14,738 one and that is the solution to the inequality. 61 00:04:15,930 --> 00:04:19,269 In Equalities can be represented on the number line. 62 00:04:21,320 --> 00:04:25,340 Here are solution is X is greater than minus one. 63 00:04:26,240 --> 00:04:28,478 So we start at minus one. 64 00:04:30,280 --> 00:04:32,667 And this line shows the range of 65 00:04:32,667 --> 00:04:35,108 values. The decks can take. 66 00:04:36,300 --> 00:04:40,152 I'm going to put an open circle there. That open circle denotes 67 00:04:40,152 --> 00:04:42,078 that although the line goes to 68 00:04:42,078 --> 00:04:46,637 minus one. X cannot actually equal minus. 1X has to be 69 00:04:46,637 --> 00:04:47,969 greater than minus one. 70 00:04:49,200 --> 00:04:55,404 Let's have a look at another 71 00:04:55,404 --> 00:04:56,438 one. 72 00:04:58,440 --> 00:05:01,428 4X plus 6. 73 00:05:02,060 --> 00:05:05,798 Is greater than 3X plus 7. 74 00:05:07,210 --> 00:05:12,310 First of all, I'm going to subtract 6 from both sides, so 75 00:05:12,310 --> 00:05:16,985 we get 4X on the left, greater than 3X plus one. 76 00:05:17,920 --> 00:05:22,535 And now I'm going to subtract 3 X from both sides, which gives 77 00:05:22,535 --> 00:05:24,310 me X greater than one. 78 00:05:25,080 --> 00:05:29,040 And again, I can represent this on the number line. 79 00:05:29,780 --> 00:05:31,810 X has to be greater than one. 80 00:05:33,680 --> 00:05:35,400 But X cannot equal 1. 81 00:05:36,990 --> 00:05:43,770 Another example is 3X minus five is less than or 82 00:05:43,770 --> 00:05:47,160 equal to 3 minus X. 83 00:05:48,860 --> 00:05:54,230 This time I need to add 5 to both sides which gives me 3X is 84 00:05:54,230 --> 00:05:56,020 less than or equal to. 85 00:05:56,530 --> 00:05:58,798 8 minus X. 86 00:05:59,440 --> 00:06:04,003 And then I need to add extra both sides, which gives me 4X 87 00:06:04,003 --> 00:06:06,109 less than or equal to 8. 88 00:06:06,890 --> 00:06:11,944 Finally, I can divide both sides by two, which gives me X is less 89 00:06:11,944 --> 00:06:13,749 than or equal to two. 90 00:06:14,980 --> 00:06:16,160 And on the number line. 91 00:06:18,830 --> 00:06:22,535 X is less than or equal to two, so we go this way. 92 00:06:23,290 --> 00:06:26,194 And this time I'm going to do a 93 00:06:26,194 --> 00:06:30,355 closed circle. This denotes that X can be equal to two. 94 00:06:33,130 --> 00:06:40,291 Now I'd like to look at the inequality minus 2X is 95 00:06:40,291 --> 00:06:42,244 greater than 4. 96 00:06:43,260 --> 00:06:46,640 In order to solve this inequality, we're going to have 97 00:06:46,640 --> 00:06:49,006 to divide both sides by minus 2. 98 00:06:51,930 --> 00:06:56,742 So we get minus two X divided by minus two is X. 99 00:06:58,060 --> 00:07:02,092 I've got to remember because I'm dividing by a negative number to 100 00:07:02,092 --> 00:07:03,100 reverse the inequality. 101 00:07:04,140 --> 00:07:09,012 And four divided by minus two is minus 2, so I get 102 00:07:09,012 --> 00:07:11,448 X is less than minus 2. 103 00:07:14,390 --> 00:07:17,330 There's often more than one way to solve an inequality. 104 00:07:18,550 --> 00:07:21,542 And I can just solve this one again by using a 105 00:07:21,542 --> 00:07:24,534 different method, so we have -2 X is greater than 4. 106 00:07:25,890 --> 00:07:28,786 If we add 2X to both sides we 107 00:07:28,786 --> 00:07:34,850 get. Zero is greater than 4 + 2 X. 108 00:07:36,700 --> 00:07:42,594 And then if we subtract 4 from both sides, we get minus four is 109 00:07:42,594 --> 00:07:44,278 greater than two X. 110 00:07:44,900 --> 00:07:50,504 And we can divide through by two again getting minus two is 111 00:07:50,504 --> 00:07:51,905 greater than X. 112 00:07:52,450 --> 00:07:57,364 And saying that X is less than minus two is the same thing as 113 00:07:57,364 --> 00:08:01,225 saying minus two is greater than X, so we've solved this 114 00:08:01,225 --> 00:08:04,384 inequality by do different methods. The second one avoids 115 00:08:04,384 --> 00:08:06,139 dividing by a negative number. 116 00:08:07,760 --> 00:08:13,907 In Equalities often appear in conjunction with the modulus 117 00:08:13,907 --> 00:08:17,150 symbol. For instance. 118 00:08:18,840 --> 00:08:22,608 We say MoD X is less than two. 119 00:08:23,700 --> 00:08:27,407 The modular symbol denotes that we have to take the absolute 120 00:08:27,407 --> 00:08:31,788 value of X regardless of sign. This is just the magnitude of X. 121 00:08:33,470 --> 00:08:36,564 And it is always positive. So for 122 00:08:36,564 --> 00:08:39,658 instance, MoD 2 is equal to 2. 123 00:08:41,010 --> 00:08:45,393 And MoD minus two is also equal to two. 124 00:08:46,850 --> 00:08:53,038 If the absolute value of X is less than two, then X must lie 125 00:08:53,038 --> 00:08:58,784 between 2:00 and minus two. We write minus two is less than X, 126 00:08:58,784 --> 00:09:00,552 is less than two. 127 00:09:01,260 --> 00:09:05,100 We can show this on the number line. 128 00:09:06,980 --> 00:09:14,792 X has to lie between minus two and two, but it can't be too 129 00:09:14,792 --> 00:09:22,370 itself. This shows the range of values that ex can take. 130 00:09:25,320 --> 00:09:31,118 If MoD X is greater than or equal to five, we have the 131 00:09:31,118 --> 00:09:36,470 absolute value of X must be greater than or equal to five, 132 00:09:36,470 --> 00:09:42,268 which means that X is going to itself is going to be greater 133 00:09:42,268 --> 00:09:48,512 than or equal to five or less than or equal to minus five. We 134 00:09:48,512 --> 00:09:54,756 write X less than or equal to minus five or X greater than or 135 00:09:54,756 --> 00:09:56,094 equal to 5. 136 00:09:56,270 --> 00:09:57,710 And on the number line. 137 00:09:59,300 --> 00:10:03,584 X can take the value 5, so we do a closed circle. 138 00:10:04,900 --> 00:10:08,004 And it can take the value minus 5. 139 00:10:10,210 --> 00:10:15,871 Now I want to look at another slightly more 140 00:10:15,871 --> 00:10:17,758 complicated modulus one. 141 00:10:18,890 --> 00:10:21,620 We have MoD X minus 4. 142 00:10:22,830 --> 00:10:24,498 Less than three. 143 00:10:25,390 --> 00:10:30,329 The modulus sign shows that the absolute value of X minus 144 00:10:30,329 --> 00:10:35,717 four is less than three. This means that X minus four must 145 00:10:35,717 --> 00:10:40,207 lie between minus three and three, so we write minus 146 00:10:40,207 --> 00:10:44,248 three less than X minus four less than three. 147 00:10:45,910 --> 00:10:50,914 This is what we call a double inequality of women's treated as 148 00:10:50,914 --> 00:10:55,918 two separate inequalities. So on the left we have minus three is 149 00:10:55,918 --> 00:10:58,003 less than X minus 4. 150 00:11:00,220 --> 00:11:06,955 By adding four to both sides, we get one is less than X. On the 151 00:11:06,955 --> 00:11:11,445 right we have X minus four is less than three. 152 00:11:12,110 --> 00:11:17,090 And again we had four to both sides to get. X is less than 7. 153 00:11:17,750 --> 00:11:21,610 So the solution to this particular inequality is X is 154 00:11:21,610 --> 00:11:26,242 greater than One X is less than Seven. We write 1 less 155 00:11:26,242 --> 00:11:30,874 than X less than Seven, and again I'll show you that on 156 00:11:30,874 --> 00:11:32,032 the number line. 157 00:11:34,510 --> 00:11:38,481 X lies between one and Seven, but it can't be either. 158 00:11:42,950 --> 00:11:49,229 Now let's solve MoD. 5X. Minus 8 159 00:11:49,229 --> 00:11:55,508 is less than or equal to 12. 160 00:11:58,000 --> 00:12:02,140 We're saying here that the absolute value of 5X minus 8 is 161 00:12:02,140 --> 00:12:04,210 less than or equal to 12. 162 00:12:05,080 --> 00:12:07,268 So 5X minus 8. 163 00:12:07,820 --> 00:12:09,460 Must be less than 12. 164 00:12:10,850 --> 00:12:13,020 Or greater than minus 12. 165 00:12:13,810 --> 00:12:20,609 We write minus 12 is less than or equal to 5X minus 8. 166 00:12:21,260 --> 00:12:23,710 Is less than or equal to 12? 167 00:12:25,030 --> 00:12:30,200 Again, we have a double inequality on the left, we have 168 00:12:30,200 --> 00:12:35,370 minus 12 is less than or equal to 5X minus 8. 169 00:12:36,480 --> 00:12:42,178 We add it to both sides, which gives us minus four is less than 170 00:12:42,178 --> 00:12:43,806 or equal to 5X. 171 00:12:44,960 --> 00:12:48,970 And then we divide both sides by 5, which gives 172 00:12:48,970 --> 00:12:53,381 us minus four fifths is less than or equal to X. 173 00:12:54,460 --> 00:12:58,708 On the right we have the inequality 5X minus 8 is less 174 00:12:58,708 --> 00:13:00,478 than or equal to 12. 175 00:13:01,480 --> 00:13:06,628 So we write 5X minus 8 less than or equal to 12. 176 00:13:07,360 --> 00:13:12,261 We had eight to both sides, which gives us 5X is less than 177 00:13:12,261 --> 00:13:13,769 or equal to 20. 178 00:13:14,510 --> 00:13:18,374 And we divide both sides by 5, which gives us X is 179 00:13:18,374 --> 00:13:20,306 less than or equal to 4. 180 00:13:22,070 --> 00:13:28,685 So our final answer is minus 4 over 5 is less than or equal to 181 00:13:28,685 --> 00:13:32,240 X. Which in turn is less than or equal to 4. 182 00:13:33,440 --> 00:13:35,834 And we can show this on the number line. 183 00:13:37,190 --> 00:13:40,010 Minus four fifths is about here. 184 00:13:40,930 --> 00:13:42,460 Let me go through to four. 185 00:13:43,160 --> 00:13:45,176 And because it's less than or 186 00:13:45,176 --> 00:13:48,860 equal to. We use a closed circle. 187 00:13:50,700 --> 00:13:54,678 In Equalities can be solved very easily using graphs, 188 00:13:54,678 --> 00:13:59,540 and if you're in any way unsure about the algebra it 189 00:13:59,540 --> 00:14:05,728 can could be a good idea to do a graph to check. Let me 190 00:14:05,728 --> 00:14:07,938 show you how this works. 191 00:14:09,700 --> 00:14:15,365 We take the inequality 2X, plus three is less than 0. 192 00:14:16,040 --> 00:14:18,992 Now this inequality can be solved very easily doing 193 00:14:18,992 --> 00:14:20,960 algebra, but it makes a good 194 00:14:20,960 --> 00:14:27,313 example. The first thing that we need to do is to draw the graph 195 00:14:27,313 --> 00:14:29,719 of Y equals 2X plus 3. 196 00:14:32,180 --> 00:14:33,638 And I've got this graph here. 197 00:14:34,200 --> 00:14:39,735 Note that it's the equation of a straight line. 198 00:14:40,440 --> 00:14:43,820 It has a slope of two and then intercept on 199 00:14:43,820 --> 00:14:45,510 the Y axis of three. 200 00:14:47,450 --> 00:14:51,278 On the X axis. 201 00:14:52,460 --> 00:14:56,308 Why is equal to 0 so that where the line cuts the X 202 00:14:56,308 --> 00:14:58,084 axis Y is equal to 0? 203 00:14:59,280 --> 00:15:01,632 Above the X axis Y is greater 204 00:15:01,632 --> 00:15:06,390 than 0. And below the X axis Y is less than 0. 205 00:15:08,260 --> 00:15:11,978 So when we say that we want 2X plus three less than 0. 206 00:15:13,420 --> 00:15:17,203 On this graph, that means why is less than zero, so we're looking 207 00:15:17,203 --> 00:15:20,404 for the points where the line is below the X axis. 208 00:15:21,090 --> 00:15:25,682 In other words, where X is less than minus one and a half, and 209 00:15:25,682 --> 00:15:27,650 this is the solution to the 210 00:15:27,650 --> 00:15:35,240 inequality. And we can mark this on the graph using the 211 00:15:35,240 --> 00:15:39,128 X axis as the number line. 212 00:15:39,850 --> 00:15:46,330 This technique can also be used with modulus inequalities 213 00:15:46,330 --> 00:15:52,810 and here using a graph can be very helpful. 214 00:15:53,750 --> 00:15:56,440 Take for example the inequality. 215 00:15:57,010 --> 00:16:00,690 MoD X minus two is less than 0. 216 00:16:01,820 --> 00:16:08,148 Again, we need to plot the graph of Y equals MoD X minus 2. 217 00:16:08,720 --> 00:16:14,924 This is the graph of Y equals MoD X minus 2. 218 00:16:15,750 --> 00:16:18,236 For those of you who are not familiar with modulus functions, 219 00:16:18,236 --> 00:16:19,592 it might look a little bit 220 00:16:19,592 --> 00:16:24,438 strange. On the right we have part of the graph of Y equals X 221 00:16:24,438 --> 00:16:29,602 minus 2. And on the left, where X is less than zero, we 222 00:16:29,602 --> 00:16:33,706 have part of the graph of Y equals minus X minus two. 223 00:16:33,706 --> 00:16:37,126 This is because the modulus function changes the sign of 224 00:16:37,126 --> 00:16:38,836 X when X is negative. 225 00:16:40,660 --> 00:16:45,580 Again, we're looking for MoD X. Minus two is less than 0. 226 00:16:46,760 --> 00:16:52,122 So we want the places where Y is less than zero, which is between 227 00:16:52,122 --> 00:16:57,101 X equals minus two and X equals +2, and again this is the 228 00:16:57,101 --> 00:16:58,633 solution to our problem. 229 00:16:59,460 --> 00:17:05,213 So we say minus two less than X less than two. 230 00:17:05,920 --> 00:17:10,526 Again, we can mark this on the graph using the X axis as the 231 00:17:10,526 --> 00:17:15,290 number line. Quadratic inequalities need 232 00:17:15,290 --> 00:17:22,130 handling with care. Let's solve X 233 00:17:22,130 --> 00:17:28,970 squared minus three X +2 is 234 00:17:28,970 --> 00:17:32,390 greater than 0. 235 00:17:35,610 --> 00:17:38,734 Note that all the terms are on the left hand side. 236 00:17:39,240 --> 00:17:42,867 And on the right hand side we just had zero, exactly as with 237 00:17:42,867 --> 00:17:43,983 the quadratic equation before 238 00:17:43,983 --> 00:17:47,654 you solve it. This expression 239 00:17:47,654 --> 00:17:53,746 factorizes too. X minus two X minus one. 240 00:17:54,530 --> 00:17:58,310 Now this is a quadratic equation. We would simply say 241 00:17:58,310 --> 00:18:02,468 right X equals 2 or X equals 1 and that's it. 242 00:18:03,250 --> 00:18:04,682 But we've got a bit more work to 243 00:18:04,682 --> 00:18:10,120 do here. Weather this expression is greater than zero is going to 244 00:18:10,120 --> 00:18:15,450 depend on the sign of each of these two factors. We sort this 245 00:18:15,450 --> 00:18:17,500 out by using a grid. 246 00:18:18,240 --> 00:18:24,744 The points that were 247 00:18:24,744 --> 00:18:31,370 checks equals. X minus 2 equals 0 and X minus 248 00:18:31,370 --> 00:18:35,390 one equals 0 and marked in, so this is one and two. 249 00:18:36,170 --> 00:18:39,579 We put the two factors on the 250 00:18:39,579 --> 00:18:42,698 left. And their product. 251 00:18:43,280 --> 00:18:47,000 Now. 252 00:18:48,210 --> 00:18:53,700 When X is less than one, both X minus one and X minus two are 253 00:18:53,700 --> 00:18:55,164 going to be negative. 254 00:18:56,580 --> 00:18:59,950 So when you multiply them together, their product is going 255 00:18:59,950 --> 00:19:00,961 to be positive. 256 00:19:03,390 --> 00:19:05,525 When X is greater than one but 257 00:19:05,525 --> 00:19:09,688 less than two. X minus one is going to be positive. 258 00:19:10,600 --> 00:19:13,096 But X minus two is going to be 259 00:19:13,096 --> 00:19:15,350 negative. So when you multiply 260 00:19:15,350 --> 00:19:17,386 them together. The product will 261 00:19:17,386 --> 00:19:23,420 be negative. Finally, when X is greater than two, both X minus 262 00:19:23,420 --> 00:19:26,556 one and X minus two will be 263 00:19:26,556 --> 00:19:30,282 positive. And if you multiply them together, their product 264 00:19:30,282 --> 00:19:31,578 will also be positive. 265 00:19:34,070 --> 00:19:35,798 We are looking for. 266 00:19:36,300 --> 00:19:39,900 X minus two times X minus one to be greater than 0. 267 00:19:40,890 --> 00:19:42,620 This occurs when it's positive. 268 00:19:43,500 --> 00:19:47,140 And our grid shows that this happens when X is less than one. 269 00:19:47,640 --> 00:19:49,866 Or when X is greater than two? 270 00:19:50,450 --> 00:19:52,418 So we write in our answer. 271 00:19:53,660 --> 00:20:00,849 Which is X is less than one or X is greater than two. 272 00:20:03,950 --> 00:20:06,590 And on the number line. 273 00:20:07,210 --> 00:20:09,388 X must be less than one. 274 00:20:09,980 --> 00:20:12,536 So I put a circle to show that it can't be 1. 275 00:20:14,280 --> 00:20:16,520 And X can also be greater than two. 276 00:20:20,050 --> 00:20:23,976 Here's another 277 00:20:23,976 --> 00:20:30,116 quadratic. Minus two X squared plus 5X 278 00:20:30,116 --> 00:20:35,480 plus 12 is greater than or equal to 0. 279 00:20:36,570 --> 00:20:40,674 I don't like having a negative coefficient of X squared, so I'm 280 00:20:40,674 --> 00:20:44,094 going to multiply this whole thing through by minus one, 281 00:20:44,094 --> 00:20:47,514 remembering to change the direction of the inequality as I 282 00:20:47,514 --> 00:20:48,882 do. This gives us. 283 00:20:49,410 --> 00:20:57,278 Two X squared minus 5X minus 12 is less than or equal to 0. 284 00:20:58,680 --> 00:21:04,906 This expression factorizes to 2X plus three times X minus four, 285 00:21:04,906 --> 00:21:08,868 so that is less than or equal 286 00:21:08,868 --> 00:21:12,955 to 0. Again, I'm going to do a grid. 287 00:21:18,150 --> 00:21:25,590 This factor is zero when X is minus 288 00:21:25,590 --> 00:21:28,380 three over 2. 289 00:21:29,450 --> 00:21:31,858 This fact is zero when X is 4. 290 00:21:32,770 --> 00:21:35,698 We write in the two factors. 291 00:21:36,380 --> 00:21:39,938 And we right in the product. 292 00:21:43,460 --> 00:21:50,530 When X is less than minus three over 2, both 2X plus three and 293 00:21:50,530 --> 00:21:53,055 X minus four and negative. 294 00:21:53,860 --> 00:21:56,110 So their product is positive. 295 00:21:57,580 --> 00:22:01,350 When X lies between minus three over two and four. 296 00:22:02,540 --> 00:22:04,670 2X plus three is positive. 297 00:22:05,410 --> 00:22:09,590 But X minus four is still negative, so their product 298 00:22:09,590 --> 00:22:10,426 is negative. 299 00:22:11,480 --> 00:22:16,797 When X is greater than four, both 2X plus three and X minus 300 00:22:16,797 --> 00:22:18,024 four are positive. 301 00:22:18,590 --> 00:22:20,180 So their product is positive. 302 00:22:20,780 --> 00:22:26,576 We are looking for 2X plus three times X minus four to be less 303 00:22:26,576 --> 00:22:28,646 than or equal to 0. 304 00:22:29,330 --> 00:22:33,110 In other words, this expression has to be either 0 or negative. 305 00:22:34,300 --> 00:22:35,270 This occurs. 306 00:22:36,520 --> 00:22:41,824 When X lies between minus three over two and four, and it can 307 00:22:41,824 --> 00:22:47,128 equal either number. So we have minus three over 2 is less than 308 00:22:47,128 --> 00:22:51,616 or equal to X is less than or equal to 4. 309 00:22:53,890 --> 00:22:56,370 And on the number line. 310 00:22:58,220 --> 00:23:00,326 Minus three over 2 is here. 311 00:23:01,760 --> 00:23:05,738 Four is here. 312 00:23:08,840 --> 00:23:12,040 And I've done filled circles because we have 313 00:23:12,040 --> 00:23:14,040 less than or equal to. 314 00:23:17,260 --> 00:23:22,783 Quadratic inequalities can also be solved graphically. 315 00:23:22,783 --> 00:23:30,673 Let's solve X squared minus three X +2 is greater 316 00:23:30,673 --> 00:23:32,251 than 0. 317 00:23:34,130 --> 00:23:38,710 As with the linear equalities inequalities, we have to plot 318 00:23:38,710 --> 00:23:43,748 the graph of Y equals X squared minus three X +2. 319 00:23:44,650 --> 00:23:51,527 This factorizes to give Y equals X minus one times X minus 2. 320 00:23:52,800 --> 00:23:54,600 The graph looks like this. 321 00:23:55,960 --> 00:24:01,174 Because it's a quadratic, it's a parabola. Are U shaped curve? 322 00:24:02,210 --> 00:24:04,275 And it crosses the X axis where 323 00:24:04,275 --> 00:24:08,729 X equals 1. Because of the factor X minus one and where 324 00:24:08,729 --> 00:24:12,139 X equals 2 because of the factor X minus 2. 325 00:24:13,490 --> 00:24:18,963 Now we're looking for X squared minus three X +2 to be greater 326 00:24:18,963 --> 00:24:23,662 than 0. This is where Y is greater than zero. In 327 00:24:23,662 --> 00:24:27,042 other words, the part of the graph that is above 328 00:24:27,042 --> 00:24:31,098 the X axis, which are the two arms of the you here. 329 00:24:32,710 --> 00:24:36,021 This occurs where X is less than 330 00:24:36,021 --> 00:24:41,218 one. And where X is greater than two, so we can write 331 00:24:41,218 --> 00:24:43,058 that in as our solution. 332 00:24:46,140 --> 00:24:52,040 And we can mark this in using the X axis 333 00:24:52,040 --> 00:24:54,400 as the number line. 334 00:24:55,600 --> 00:25:00,222 I'll do 335 00:25:00,222 --> 00:25:04,844 one more 336 00:25:04,844 --> 00:25:07,155 quadratic 337 00:25:07,155 --> 00:25:09,466 inequality. 338 00:25:10,470 --> 00:25:14,040 X squared Minus X 339 00:25:14,040 --> 00:25:18,419 minus 6. So less than or equal to 0. 340 00:25:22,680 --> 00:25:27,146 Again, we need to plot the graph of Y equals X 341 00:25:27,146 --> 00:25:29,176 squared minus X minus 6. 342 00:25:30,360 --> 00:25:32,058 The expression factorizes. 343 00:25:32,830 --> 00:25:35,998 To X minus three. 344 00:25:36,070 --> 00:25:40,029 X +2 And the graph 345 00:25:40,029 --> 00:25:46,756 looks like this. Similar to the previous 346 00:25:46,756 --> 00:25:48,040 graph. 347 00:25:49,210 --> 00:25:54,716 We have The factor X +2 the line crosses the point at X equals 348 00:25:54,716 --> 00:25:58,832 minus two and for the factor X minus three, the curve crosses 349 00:25:58,832 --> 00:26:00,890 the point at X equals 3. 350 00:26:01,750 --> 00:26:06,046 And we're looking for where X squared minus X minus six is 351 00:26:06,046 --> 00:26:08,194 less than or equal to 0. 352 00:26:09,470 --> 00:26:14,189 In other words, why must lie on the X axis or below it? 353 00:26:14,920 --> 00:26:19,509 This part of the curve and that occurs between the points of X 354 00:26:19,509 --> 00:26:24,804 equals minus two and X equals 3. So we can say that minus two is 355 00:26:24,804 --> 00:26:29,746 less than or equal to X, which is less than or equal to 3. 356 00:26:31,260 --> 00:26:36,746 And we can put this in again using the X axis is the 357 00:26:36,746 --> 00:26:40,966 number line from minus 2 using a closed circle because 358 00:26:40,966 --> 00:26:43,920 2 - 2 is included to +3.