1 00:00:00,000 --> 00:00:03,630 >> Hello, this is Dr. Cynthia Furse at the University of Utah. 2 00:00:03,630 --> 00:00:07,755 Today, we're going to talk about Operational Amplifiers or Op Amps. 3 00:00:07,755 --> 00:00:11,835 Remember that electrical engineering is about what you can do to a voltage. 4 00:00:11,835 --> 00:00:16,665 For example, a resistor converts voltage to current, and current to voltage. 5 00:00:16,665 --> 00:00:21,345 A voltage divider divides the voltage, and a current divider divides the current. 6 00:00:21,345 --> 00:00:26,130 We can think of this as the operation of a voltage divider or a current divider. 7 00:00:26,130 --> 00:00:29,265 Here's the circuit that goes with that operation. 8 00:00:29,265 --> 00:00:31,380 Why do we need an Op Amp? 9 00:00:31,380 --> 00:00:33,780 Because there are many more operations that we would 10 00:00:33,780 --> 00:00:36,300 like to do than the devices that we have today. 11 00:00:36,300 --> 00:00:40,905 For example, an Op Amp circuit can amplify or multiply voltages. 12 00:00:40,905 --> 00:00:43,275 It can de-amplify or divide them. 13 00:00:43,275 --> 00:00:45,575 It can add, subtract, compare. 14 00:00:45,575 --> 00:00:46,999 It could switch voltages, 15 00:00:46,999 --> 00:00:50,560 and many more operations can be done with Op Amp circuits. 16 00:00:50,560 --> 00:00:52,425 So, what is an Op Amp? 17 00:00:52,425 --> 00:00:55,640 The Op Amps we use are going to come into the little chip like this. 18 00:00:55,640 --> 00:00:57,365 There are eight pins on this chip. 19 00:00:57,365 --> 00:01:01,370 This will fit into your protoboard and you can see chips one, two, three, four, 20 00:01:01,370 --> 00:01:06,555 and here, the pin numbers start with this little dot here at the top. 21 00:01:06,555 --> 00:01:09,600 On pin two, we have an input Vn, 22 00:01:09,600 --> 00:01:11,070 that's our negative input, 23 00:01:11,070 --> 00:01:13,500 and there's a Vp input on pin three, 24 00:01:13,500 --> 00:01:14,955 that's the positive input. 25 00:01:14,955 --> 00:01:17,130 Pin six has the V output. 26 00:01:17,130 --> 00:01:21,035 So, there are two voltage inputs and there's one voltage output. 27 00:01:21,035 --> 00:01:25,690 This triangle right here is the symbol that we use to represent the Op-Amp. 28 00:01:25,690 --> 00:01:29,555 The Op Amp is different than other devices that we have used in the past. 29 00:01:29,555 --> 00:01:31,040 A resistor, for example, 30 00:01:31,040 --> 00:01:34,880 always acts like a resistor even if we don't have it connected to power. 31 00:01:34,880 --> 00:01:36,590 But an Op Amp only acts like 32 00:01:36,590 --> 00:01:41,000 an operational amplifier if we connect it to its outside power supply, 33 00:01:41,000 --> 00:01:43,520 Vcc and minus Vcc. 34 00:01:43,520 --> 00:01:44,975 This is very important. 35 00:01:44,975 --> 00:01:48,455 Keep your eye on the Vcc as we go through this lecture. 36 00:01:48,455 --> 00:01:51,245 This is what's inside the amplifier. 37 00:01:51,245 --> 00:01:52,985 This is what's inside that triangle. 38 00:01:52,985 --> 00:01:54,470 Here is the negative input, 39 00:01:54,470 --> 00:01:56,435 the positive input, and the output. 40 00:01:56,435 --> 00:01:59,240 You can see there are a series of transistors that are hooked up in 41 00:01:59,240 --> 00:02:03,350 this fashion that make the operational amplifier do what we want it to do. 42 00:02:03,350 --> 00:02:09,440 However, these transistors only work if they are connected to Vcc and minus Vcc. 43 00:02:09,440 --> 00:02:12,565 This is why the amplifier is an active device. 44 00:02:12,565 --> 00:02:16,955 Without this power, it does not act like an operational amplifier. 45 00:02:16,955 --> 00:02:19,190 Okay. So, now that we know that we have 46 00:02:19,190 --> 00:02:21,875 this triangle that represents an operational amplifier, 47 00:02:21,875 --> 00:02:23,225 if we want to hook it up, 48 00:02:23,225 --> 00:02:26,915 we're going to hook it up this way with plus and minus Vcc. 49 00:02:26,915 --> 00:02:28,790 But that's complicated to draw, 50 00:02:28,790 --> 00:02:33,410 and we really just remember that we have Vcc and we normally draw it this way. 51 00:02:33,410 --> 00:02:36,470 Another thing to remember is all of those transistors in there, 52 00:02:36,470 --> 00:02:40,435 they divide the frontend and the backend of the amplifier in effect. 53 00:02:40,435 --> 00:02:45,635 So, even though we might have a positive current here and a negative current there, 54 00:02:45,635 --> 00:02:48,935 because there are all of those transistors and the power supply, 55 00:02:48,935 --> 00:02:52,690 sometimes current gets added and sometimes current gets subtracted. 56 00:02:52,690 --> 00:02:54,720 We don't really know in advance. 57 00:02:54,720 --> 00:02:57,715 So, all we can say is that i zero, the output current, 58 00:02:57,715 --> 00:03:02,190 is not equal to the sum of the two input currents. 59 00:03:02,930 --> 00:03:05,805 Now, let's talk about Op Amp Gain. 60 00:03:05,805 --> 00:03:08,465 Op Amp Gain is intrinsic to the amplifier. 61 00:03:08,465 --> 00:03:11,090 It's controlled by how the transistors are put together. 62 00:03:11,090 --> 00:03:13,070 It's sometimes also called Open Loop Gain. 63 00:03:13,070 --> 00:03:15,875 Op Amps have a very high voltage gain 64 00:03:15,875 --> 00:03:19,310 typically on the order of 10 to the fourth to 10 to the eighth. 65 00:03:19,310 --> 00:03:21,315 They also have a linear response. 66 00:03:21,315 --> 00:03:27,740 So, the gain tells us that the output is equal to the gain times the input. 67 00:03:27,740 --> 00:03:30,050 In this case, the input is considered to be 68 00:03:30,050 --> 00:03:33,440 the difference between the positive and negative inputs of the Op Amp. 69 00:03:33,440 --> 00:03:37,035 So, if we have a voltage gain of 10 to the fourth, 70 00:03:37,035 --> 00:03:38,790 it would be linear of something like this, 71 00:03:38,790 --> 00:03:41,990 a voltage gain of 10 to the eighth would be steeper. 72 00:03:41,990 --> 00:03:44,070 Because we have Vcc, 73 00:03:44,070 --> 00:03:46,080 remember I said follow Vcc, 74 00:03:46,080 --> 00:03:49,505 it limits the actual output of our operational amplifier. 75 00:03:49,505 --> 00:03:51,860 We cannot put out more power or 76 00:03:51,860 --> 00:03:54,990 more voltage than we were able to put in to our amplifier. 77 00:03:54,990 --> 00:03:59,015 So, our amplifier circuit always saturates at plus Vcc 78 00:03:59,015 --> 00:04:04,080 and minus Vcc because of the power supply limitations. 79 00:04:04,700 --> 00:04:10,375 Let's see how that saturation can help the operational amplifier acts like a switch. 80 00:04:10,375 --> 00:04:13,780 Here is a circuit where we hooked up our amplifier and we want to 81 00:04:13,780 --> 00:04:17,584 be able to control if a red or a green LED turns on. 82 00:04:17,584 --> 00:04:23,425 So, we've connected our negative input right here to ground along with our two LEDs. 83 00:04:23,425 --> 00:04:26,350 Remember that the LED only turns on if current 84 00:04:26,350 --> 00:04:29,690 goes through it in this direction because of its diode nature. 85 00:04:29,690 --> 00:04:32,800 So, let's see what happens if we put a voltage, 86 00:04:32,800 --> 00:04:35,380 let's say, two volts, on our positive input. 87 00:04:35,380 --> 00:04:41,200 In that case, remember that Vp minus Vn is the thing that we're interested in, 88 00:04:41,200 --> 00:04:43,840 and that's two minus zero in this case. 89 00:04:43,840 --> 00:04:46,485 So, it's two volts, two volts minus zero volts. 90 00:04:46,485 --> 00:04:49,935 Multiply that by a very large value, let's say, 10,000. 91 00:04:49,935 --> 00:04:54,335 So, our output voltage tries to go up to be 20,000. 92 00:04:54,335 --> 00:04:58,140 Well, the limitation of the power supply limits that, 93 00:04:58,140 --> 00:04:59,370 let's say, to 12 volts. 94 00:04:59,370 --> 00:05:01,795 So, the output voltage right here is 12. 95 00:05:01,795 --> 00:05:06,200 Aha! But that's very good because that gives us a twelve volt difference across 96 00:05:06,200 --> 00:05:11,075 our LED that drives the current in this direction and turns on our red LED. 97 00:05:11,075 --> 00:05:14,450 The green LED is trying to drive current in this direction, 98 00:05:14,450 --> 00:05:19,140 but the LED acts like an open circuit because of a diode and it doesn't turn on. 99 00:05:19,140 --> 00:05:23,300 Now, let's see what happens if we put a negative voltage on Vp instead. 100 00:05:23,300 --> 00:05:27,110 Then, Vp minus Vn is going to be minus two volts. 101 00:05:27,110 --> 00:05:31,820 Multiply that by a very large number and it tries to go to, say, minus 20,000. 102 00:05:31,820 --> 00:05:34,440 But it's limited by the power supply voltage, 103 00:05:34,440 --> 00:05:36,290 so it goes to minus 12. 104 00:05:36,290 --> 00:05:39,470 Well, if it's trying to drive current through here, 105 00:05:39,470 --> 00:05:41,630 the red LED acts like 106 00:05:41,630 --> 00:05:45,305 a diode and doesn't allow current to go through. It doesn't turn on. 107 00:05:45,305 --> 00:05:48,260 Oops! Sorry, I'm not trying to drive current in that direction. 108 00:05:48,260 --> 00:05:50,270 I'm actually trying to pull current in that direction. 109 00:05:50,270 --> 00:05:52,160 The green LED, however, 110 00:05:52,160 --> 00:05:56,935 does turn on because here goes the direction of the current for the green LED. 111 00:05:56,935 --> 00:05:59,740 So, if we make Vp positive, 112 00:05:59,740 --> 00:06:01,760 we can turn on the red LED, 113 00:06:01,760 --> 00:06:03,170 and if we make it negative, 114 00:06:03,170 --> 00:06:05,075 we can turn on the green LED. 115 00:06:05,075 --> 00:06:10,140 This allows us to have a circuit that acts like a switch for our two LEDs. 116 00:06:10,640 --> 00:06:14,390 Now, let's talk about Op Amp Gain versus Circuit Gain. 117 00:06:14,390 --> 00:06:18,320 The op-amp gain is always high and it's intrinsic to the inside of the op-amp. 118 00:06:18,320 --> 00:06:21,065 It's also called the open-loop gain or the voltage gain. 119 00:06:21,065 --> 00:06:25,790 Gain is typically defined as the output divided by the input, and in this case, 120 00:06:25,790 --> 00:06:31,035 the input is considered to be the difference of the two inputs. 121 00:06:31,035 --> 00:06:32,860 Circuit gain, on the other hand, 122 00:06:32,860 --> 00:06:36,910 we may have an op-amp in here and connect it up in this fashion. 123 00:06:36,910 --> 00:06:38,600 Connect the output right there. 124 00:06:38,600 --> 00:06:41,510 The circuit gain tells us about the op-amp that has 125 00:06:41,510 --> 00:06:44,960 its gain A for all of the other resistors around it also. 126 00:06:44,960 --> 00:06:47,720 Depending on how we connect up our op-amp circuit, 127 00:06:47,720 --> 00:06:49,625 gain can be large or small. 128 00:06:49,625 --> 00:06:52,715 If it's large, larger than one, that's amplification. 129 00:06:52,715 --> 00:06:54,680 Less than one is deamplification. 130 00:06:54,680 --> 00:06:56,210 If the gain is negative, 131 00:06:56,210 --> 00:06:57,350 we call it inverting, 132 00:06:57,350 --> 00:06:58,535 and if the gain is positive, 133 00:06:58,535 --> 00:07:00,780 we call it non-inverting. 134 00:07:01,160 --> 00:07:04,775 Here's a non-ideal op-amp equivalent circuit. 135 00:07:04,775 --> 00:07:09,245 Notice that right here is a dependent voltage source that depends on 136 00:07:09,245 --> 00:07:14,005 the gain and the difference between the two input voltages. 137 00:07:14,005 --> 00:07:16,420 So, for a non-ideal op-amp, 138 00:07:16,420 --> 00:07:19,040 we recognize that Ri is very large. 139 00:07:19,040 --> 00:07:22,265 It's typically on the order of 10 to six to the 10 to the 13th. 140 00:07:22,265 --> 00:07:25,115 A is very large, 10 to the fourth to 10 to the eighth. 141 00:07:25,115 --> 00:07:27,215 The output resistance is very small, 142 00:07:27,215 --> 00:07:30,350 one to a 100, and the supply voltage right here, 143 00:07:30,350 --> 00:07:33,005 Vcc and minus Vcc, 144 00:07:33,005 --> 00:07:34,535 and sometimes they draw it that way too, 145 00:07:34,535 --> 00:07:36,580 is five to 24 volts. 146 00:07:36,580 --> 00:07:39,605 Now, for an ideal op-amp, it's going to be different. 147 00:07:39,605 --> 00:07:40,920 For an ideal op-amp, 148 00:07:40,920 --> 00:07:46,220 we're going to assume that the input resistance is so large that it can be eliminated. 149 00:07:46,220 --> 00:07:50,015 In that case, it's like having an open circuit right there at the input. 150 00:07:50,015 --> 00:07:56,589 We can consider that the gain is so large that we can say Vp is equal to Vn, 151 00:07:56,589 --> 00:07:59,045 and we can say that the output resistance is so 152 00:07:59,045 --> 00:08:02,495 small that we can neglect it and consider it just as a wire. 153 00:08:02,495 --> 00:08:06,005 The implications of this are that for an ideal op-amp, 154 00:08:06,005 --> 00:08:08,420 we can say that Vp equal Vn, 155 00:08:08,420 --> 00:08:13,385 and we can say that no current goes into the either input of this op-amp. 156 00:08:13,385 --> 00:08:16,280 Sometimes it's also useful to remember, 157 00:08:16,280 --> 00:08:19,415 right here, that R out is equal to zero. 158 00:08:19,415 --> 00:08:21,900 You'll see why we need that in a minute. 159 00:08:22,250 --> 00:08:25,730 Okay. So, the circuit gain depends on the circuit. 160 00:08:25,730 --> 00:08:26,960 In this red box, 161 00:08:26,960 --> 00:08:29,540 I have an example of a non-inverting amplifier. 162 00:08:29,540 --> 00:08:34,534 Trust me for now that the output is going to be equal to 163 00:08:34,534 --> 00:08:41,929 R1 plus R2 over R2 times Vs for this particular op-amp circuit. 164 00:08:41,929 --> 00:08:44,225 In that case, we call this the gain, 165 00:08:44,225 --> 00:08:47,330 G, and we can see that it's always positive. 166 00:08:47,330 --> 00:08:49,395 That's because resistors are always positive. 167 00:08:49,395 --> 00:08:52,750 So, it's non-inverting, it's always positive. 168 00:08:52,750 --> 00:08:58,760 Now, let's see if this non-inverting amplifier can go to any value we want. 169 00:08:58,760 --> 00:09:04,190 No. Because we have this Vcc and minus Vcc, 170 00:09:04,190 --> 00:09:07,745 so we know that the gain has to be limited by Vcc. 171 00:09:07,745 --> 00:09:11,200 So, the op-amp gain is intrinsic to the amplifier, 172 00:09:11,200 --> 00:09:16,230 but the circuit gain depends on all of the resistors that we put around it. 173 00:09:16,310 --> 00:09:21,430 So, in summary, here are the important things to remember about an op-amp. 174 00:09:21,430 --> 00:09:23,710 Here is a model of a non-ideal op-amp. 175 00:09:23,710 --> 00:09:25,510 We're actually not going to use that very much in 176 00:09:25,510 --> 00:09:28,060 this class but I want you to remember these parameters. 177 00:09:28,060 --> 00:09:31,945 We are going to use the ideal op-amp model extensively. 178 00:09:31,945 --> 00:09:33,790 Remember that the important features of 179 00:09:33,790 --> 00:09:37,390 the non-ideal op-amp are that the negative and positive input are equal, 180 00:09:37,390 --> 00:09:39,820 that no current goes into either input, 181 00:09:39,820 --> 00:09:43,765 and that the output is not the sum of the two input currents. 182 00:09:43,765 --> 00:09:47,540 Remember also that we have Vcc and minus 183 00:09:47,540 --> 00:09:52,715 Vcc that limit the output voltage of our operational amplifier. 184 00:09:52,715 --> 00:09:55,750 Now, I hope you're wondering where the picture was on the front. 185 00:09:55,750 --> 00:10:00,130 That is the Wild Horse Corral on Antelope Island.