0:00:00.000,0:00:00.660 0:00:00.660,0:00:02.340 Fischer projections[br]are another way 0:00:02.340,0:00:04.660 of visualizing molecules[br]in three dimensions. 0:00:04.660,0:00:07.570 And let's use the[br]example of lactic acid. 0:00:07.570,0:00:09.070 It's called lactic[br]acid since it has 0:00:09.070,0:00:12.200 a carboxylic acid functional[br]group over here on the right. 0:00:12.200,0:00:15.260 And this is the only chirality[br]center in lactic acid. 0:00:15.260,0:00:17.530 It's an sp3 hybridized[br]carbon with four 0:00:17.530,0:00:19.400 different substituents[br]attached to it. 0:00:19.400,0:00:20.890 So with only one[br]chirality center, 0:00:20.890,0:00:23.690 we would expect to[br]have two stereoisomers 0:00:23.690,0:00:25.050 for this molecule. 0:00:25.050,0:00:27.940 And those stereoisomers would[br]be enantiomers of each other. 0:00:27.940,0:00:30.470 Over here, I've picked[br]one of those enantiomers. 0:00:30.470,0:00:32.420 And I've just drawn[br]it in this fashion. 0:00:32.420,0:00:34.630 Let's see which enantiomer[br]we have over here. 0:00:34.630,0:00:36.780 Well, this is my[br]chirality center, 0:00:36.780,0:00:38.440 the one attached to my OH. 0:00:38.440,0:00:40.720 And if I were to assign[br]absolute configuration 0:00:40.720,0:00:43.400 to that chirality center,[br]I look at the first atom 0:00:43.400,0:00:45.065 connected to that[br]chirality center. 0:00:45.065,0:00:47.590 Well, that's oxygen[br]versus carbon 0:00:47.590,0:00:49.550 versus a carbon over[br]here in my carbonyl. 0:00:49.550,0:00:52.120 So obviously,[br]oxygen's going to win. 0:00:52.120,0:00:55.390 So we can assign oxygen[br]a number 1 priority 0:00:55.390,0:00:57.390 since it has the[br]highest atomic number. 0:00:57.390,0:01:01.180 And when I compare these[br]two carbons to each other, 0:01:01.180,0:01:04.560 I know the carbon on the right[br]is double bonded to an oxygen. 0:01:04.560,0:01:07.210 So that's going to give it[br]higher priority than the carbon 0:01:07.210,0:01:09.820 over here on the left since[br]that's bonded to hydrogens. 0:01:09.820,0:01:12.970 And then my other hydrogen[br]attached to my chirality center 0:01:12.970,0:01:15.000 is going away from me in space. 0:01:15.000,0:01:17.380 So when I'm assigning[br]absolute configuration, 0:01:17.380,0:01:19.930 I look at the fact that[br]it's going one, two, three. 0:01:19.930,0:01:21.080 It's going around this way. 0:01:21.080,0:01:22.470 It's going around clockwise. 0:01:22.470,0:01:25.620 Therefore, this is the R[br]enantiomer of lactic acid. 0:01:25.620,0:01:27.500 So that's all from[br]a previous video. 0:01:27.500,0:01:30.940 Now, if I want to draw a Fischer[br]projection of R lactic acid, 0:01:30.940,0:01:34.070 what I would do is I would[br]put my eye right here. 0:01:34.070,0:01:36.775 And I would stare down[br]at my chirality center. 0:01:36.775,0:01:39.990 0:01:39.990,0:01:42.740 And I would draw[br]exactly what I see. 0:01:42.740,0:01:44.880 Well, if I'm staring[br]down this way, 0:01:44.880,0:01:47.250 I could draw a line[br]right here to represent 0:01:47.250,0:01:49.390 my flat sheet of paper. 0:01:49.390,0:01:52.760 And I can see that both[br]my hydrogen and my OH 0:01:52.760,0:01:56.200 are above my sheet of paper,[br]whereas my carboxylic acid 0:01:56.200,0:01:59.140 and my CH3 are below[br]my sheet of paper. 0:01:59.140,0:02:02.940 So this carbon is my[br]chirality center carbon. 0:02:02.940,0:02:07.460 And I have my OH[br]coming out at me. 0:02:07.460,0:02:10.220 And this is actually going[br]to be on the right side. 0:02:10.220,0:02:12.552 So if you take out your[br]molecular model set, 0:02:12.552,0:02:14.510 you will see this OH will[br]be coming out at you. 0:02:14.510,0:02:16.660 And it will be on the[br]right side of you. 0:02:16.660,0:02:18.562 And this hydrogen will[br]be coming out at you, 0:02:18.562,0:02:20.187 and it will be on[br]the left side of you. 0:02:20.187,0:02:22.800 So that hydrogen would[br]go over here like that. 0:02:22.800,0:02:25.940 This carboxylic acid[br]functional group-- this 0:02:25.940,0:02:27.580 is the top my head right here. 0:02:27.580,0:02:30.610 Then that would make this go at[br]the top of what I'm looking at. 0:02:30.610,0:02:33.190 And so that is going[br]away from me in space. 0:02:33.190,0:02:35.480 So we would use a dash[br]to represent that. 0:02:35.480,0:02:39.530 And so we could go ahead and[br]draw our C double bond to an O. 0:02:39.530,0:02:41.700 And then an OH[br]going away from me. 0:02:41.700,0:02:44.328 And then if I look at[br]this CH3 group over here, 0:02:44.328,0:02:45.536 it's also going away from me. 0:02:45.536,0:02:46.770 It's going down in space. 0:02:46.770,0:02:51.220 So I can represent it going[br]down in space like that. 0:02:51.220,0:02:54.160 And this is the viewpoint[br]of a Fischer projection. 0:02:54.160,0:02:56.890 So if I'm going to convert[br]this into a Fischer projection, 0:02:56.890,0:03:00.680 a Fischer projection is just[br]drawing a cross like that. 0:03:00.680,0:03:03.060 And then at the top, you[br]have your C double bonded 0:03:03.060,0:03:05.070 to an O and then[br]an OH as just a way 0:03:05.070,0:03:08.420 of abbreviating this carboxylic[br]acid functional group. 0:03:08.420,0:03:10.240 And then I have a[br]hydrogen over here. 0:03:10.240,0:03:12.510 And then I have an[br]OH group over here. 0:03:12.510,0:03:13.990 And then I have a CH3 here. 0:03:13.990,0:03:16.280 So this is a Fischer projection. 0:03:16.280,0:03:19.290 This is the Fischer[br]projection for R lactic acid. 0:03:19.290,0:03:21.130 So this is R lactic acid. 0:03:21.130,0:03:24.040 And Fischer projections[br]were invented 0:03:24.040,0:03:27.967 by Emil Fischer, who won the[br]Nobel Prize in chemistry. 0:03:27.967,0:03:30.300 One of the things was for his[br]research in carbohydrates. 0:03:30.300,0:03:33.579 And he drew Fischer projections[br]to help him draw carbohydrates. 0:03:33.579,0:03:35.870 And so that's where you'll[br]see Fischer projections used 0:03:35.870,0:03:37.953 most often, even though[br]some chemists don't really 0:03:37.953,0:03:38.870 like them very much. 0:03:38.870,0:03:41.570 So this is the Fischer[br]projection for R lactic acid. 0:03:41.570,0:03:44.480 And if I wanted to draw the[br]Fischer projection for S 0:03:44.480,0:03:47.360 lactic acid, I[br]would just reflect 0:03:47.360,0:03:49.500 this molecule in a mirror. 0:03:49.500,0:03:52.840 So let's see if I can fit[br]my mirror in over here. 0:03:52.840,0:03:57.250 And I would have my OH[br]reflected in my mirror. 0:03:57.250,0:04:00.660 And then I'd go ahead and[br]draw my Fischer projection. 0:04:00.660,0:04:03.170 And then my methyl group[br]would be over here. 0:04:03.170,0:04:04.950 My hydrogen would be over here. 0:04:04.950,0:04:07.760 And my carboxylic[br]acid functional group 0:04:07.760,0:04:08.720 would be right there. 0:04:08.720,0:04:11.190 So this would be S lactic[br]acid on the right and R 0:04:11.190,0:04:13.490 lactic acid on the left. 0:04:13.490,0:04:16.579 S lactic acid is the[br]type of lactic acid 0:04:16.579,0:04:20.649 you find in the buildup of[br]muscles after extreme exercise. 0:04:20.649,0:04:22.880 And the type of lactic[br]acid that some people have 0:04:22.880,0:04:26.800 heard of from milk is[br]actually a racemic mixture. 0:04:26.800,0:04:30.780 So the bacteria in sour milk[br]will break down the lactose 0:04:30.780,0:04:36.010 into a 50% mixture of R and a[br]50% mixture of S lactic acid. 0:04:36.010,0:04:38.210 Let's take a look[br]at a carbohydrate, 0:04:38.210,0:04:42.100 since Fischer used Fischer[br]projections for carbohydrates, 0:04:42.100,0:04:42.730 specifically. 0:04:42.730,0:04:45.190 So here I have a carbohydrate. 0:04:45.190,0:04:48.280 And if I were to number[br]this carbohydrate, 0:04:48.280,0:04:51.630 this carbonyl would[br]get a number 1. 0:04:51.630,0:04:54.180 And then this would get[br]a number 2 over here, 0:04:54.180,0:04:56.360 a number 4, and a number 4. 0:04:56.360,0:04:58.540 This is a four-carbon[br]carbohydrate. 0:04:58.540,0:05:01.830 How many stereoisomers does[br]this carbohydrate have? 0:05:01.830,0:05:06.110 Well, this carbon number[br]2 is a chirality center. 0:05:06.110,0:05:09.700 And carbon number 3[br]is a chirality center, 0:05:09.700,0:05:11.690 so 2 chirality centers. 0:05:11.690,0:05:14.360 So I use the formula[br]of 2 to the n, 0:05:14.360,0:05:16.390 where n is the number[br]of chirality centers. 0:05:16.390,0:05:21.250 So I would expect 2 squared,[br]or 4 possible stereoisomers 0:05:21.250,0:05:22.140 for this molecule. 0:05:22.140,0:05:24.120 So you could draw four[br]different stereoisomers 0:05:24.120,0:05:24.960 for this molecule. 0:05:24.960,0:05:26.600 We'll draw them[br]in a few minutes. 0:05:26.600,0:05:30.660 For right now, I've gone[br]ahead and drawn one of them 0:05:30.660,0:05:32.510 as a sawhorse projection. 0:05:32.510,0:05:35.490 So here I have a sawhorse[br]projection of one 0:05:35.490,0:05:38.340 of the possible stereoisomers. 0:05:38.340,0:05:40.220 And what we're[br]going to do is we're 0:05:40.220,0:05:43.320 going to put our[br]eye right up here. 0:05:43.320,0:05:47.940 And we're going to stare[br]straight down at this bond 0:05:47.940,0:05:48.670 right here. 0:05:48.670,0:05:50.790 And we're going to see if[br]we can draw the Fischer 0:05:50.790,0:05:52.350 projection for this molecule. 0:05:52.350,0:05:54.500 So what do we see? 0:05:54.500,0:05:58.620 Well, let's start with[br]this carbon right up here. 0:05:58.620,0:06:00.790 So we'll make that[br]carbon this one. 0:06:00.790,0:06:06.830 And you can see that the[br]OH attached to that carbon 0:06:06.830,0:06:07.920 is going to the right. 0:06:07.920,0:06:10.000 And it's going up at us. 0:06:10.000,0:06:14.080 So that OH is going to the[br]right, and it's going up at us. 0:06:14.080,0:06:17.250 And then if I look at[br]this hydrogen over here, 0:06:17.250,0:06:17.960 it's on the left. 0:06:17.960,0:06:19.590 And it's going up at us. 0:06:19.590,0:06:24.100 So my hydrogen is on the[br]left and it's going up at us. 0:06:24.100,0:06:29.500 And this aldehyde functional[br]group, this CHO, you can see 0:06:29.500,0:06:32.110 is going down. 0:06:32.110,0:06:35.110 So this aldehyde functional[br]group is going away from us. 0:06:35.110,0:06:37.170 So we can go ahead and[br]represent that aldehyde 0:06:37.170,0:06:40.820 as going away from us[br]in space like that. 0:06:40.820,0:06:44.080 Well, this chirality[br]center carbon 0:06:44.080,0:06:47.280 is connected to this[br]chirality center carbon. 0:06:47.280,0:06:49.100 So we'll go ahead and[br]draw a straight line, 0:06:49.100,0:06:50.870 since we're looking[br]straight down at it. 0:06:50.870,0:06:53.610 And once again, we will[br]find that our OH group 0:06:53.610,0:06:55.540 is on the right[br]coming out at us. 0:06:55.540,0:06:58.740 Our hydrogen is on the[br]left coming out at us. 0:06:58.740,0:07:00.700 So let's go ahead[br]and put those in. 0:07:00.700,0:07:02.890 OH group is on the[br]right coming out at us. 0:07:02.890,0:07:05.230 Hydrogen is on the[br]left coming out at us. 0:07:05.230,0:07:09.040 And then, of course, we[br]have this CH2OH down here 0:07:09.040,0:07:10.620 as going away from us in space. 0:07:10.620,0:07:14.670 So we'll go ahead and[br]draw that CH2OH going away 0:07:14.670,0:07:15.860 from us in space like that. 0:07:15.860,0:07:20.110 So that would be the Fischer[br]projection translated. 0:07:20.110,0:07:22.690 Let's go ahead and make it into[br]an actual Fischer projection 0:07:22.690,0:07:25.730 where we just go ahead[br]and draw straight lines. 0:07:25.730,0:07:27.790 And the intersection[br]of those straight lines 0:07:27.790,0:07:31.660 are where our[br]chirality centers are. 0:07:31.660,0:07:35.310 So this would be an H.[br]This would be an OH. 0:07:35.310,0:07:36.140 This would be an H. 0:07:36.140,0:07:37.250 This would be an OH. 0:07:37.250,0:07:39.050 This would be our CH2OH. 0:07:39.050,0:07:42.350 And then at the top, we[br]have our aldehyde, CHO. 0:07:42.350,0:07:45.890 So this is one of the four[br]possible stereoisomers. 0:07:45.890,0:07:47.890 And Fischer projections[br]just make it much easier 0:07:47.890,0:07:49.350 when we're working[br]with carbohydrates. 0:07:49.350,0:07:50.490 So this is one of the four. 0:07:50.490,0:07:52.450 Let's go ahead and redraw[br]the one we just drew 0:07:52.450,0:07:55.702 and let's get the other three to[br]get our total of four on here. 0:07:55.702,0:07:58.160 So I'm going to take the one[br]that I just drew on the right. 0:07:58.160,0:07:59.460 I'm going to redraw it. 0:07:59.460,0:08:01.220 I'm going to draw it a little[br]bit smaller so everything 0:08:01.220,0:08:02.055 will fit in here. 0:08:02.055,0:08:06.030 So this is one[br]possible stereoisomer. 0:08:06.030,0:08:08.910 I have my OHs on the right. 0:08:08.910,0:08:10.900 I have my hydrogens. 0:08:10.900,0:08:12.760 I have my CHO. 0:08:12.760,0:08:13.456 I have my CH2OH. 0:08:13.456,0:08:16.450 0:08:16.450,0:08:19.560 If I wanted to draw the[br]enantiomer to this molecule, 0:08:19.560,0:08:22.760 I would just have to[br]reflect it in a mirror. 0:08:22.760,0:08:24.150 So I could just do this. 0:08:24.150,0:08:27.190 I could reflect the[br]molecule in a mirror, 0:08:27.190,0:08:29.730 and I would have the enantiomer. 0:08:29.730,0:08:33.429 So this would be the[br]enantiomer to the stereoisomer 0:08:33.429,0:08:35.470 that I just drew. 0:08:35.470,0:08:38.289 If I wanted to[br]draw the other two, 0:08:38.289,0:08:39.789 I can just go ahead[br]and real quickly 0:08:39.789,0:08:42.179 put in my Fischer[br]projections right here. 0:08:42.179,0:08:44.610 So I have two more to go. 0:08:44.610,0:08:50.840 And I'm going to put the OH over[br]here, and then the H over here, 0:08:50.840,0:08:54.650 and then the OH over[br]here, and the H over here. 0:08:54.650,0:08:58.530 So this is yet another[br]possible stereoisomer. 0:08:58.530,0:09:01.530 And I'll draw the mirror[br]image over here on the right. 0:09:01.530,0:09:04.230 So I have to have a[br]hydrogen right here. 0:09:04.230,0:09:06.850 And then my OH must[br]be on this side. 0:09:06.850,0:09:11.420 And then I must have an[br]OH right here, and then 0:09:11.420,0:09:14.975 a hydrogen on the other side,[br]and then a CHO for my aldehyde, 0:09:14.975,0:09:17.200 and a CH2OH. 0:09:17.200,0:09:20.420 So here I have my four[br]possible stereoisomers 0:09:20.420,0:09:22.792 for this carbohydrate. 0:09:22.792,0:09:24.500 And I'm going to go[br]ahead and label them. 0:09:24.500,0:09:27.170 I'm going to label this[br]first one here stereoisomer 0:09:27.170,0:09:31.760 A, stereoisomer B, stereoisomer[br]C, and stereoisomer D. 0:09:31.760,0:09:34.860 Well, C and D are mirror[br]images of each other. 0:09:34.860,0:09:37.169 So they are enantiomers[br]of each other. 0:09:37.169,0:09:38.210 So these are enantiomers. 0:09:38.210,0:09:40.820 A and B are mirror[br]images, so they 0:09:40.820,0:09:42.790 are enantiomers to each other. 0:09:42.790,0:09:45.600 And then we talked about[br]in the diastereomer video, 0:09:45.600,0:09:51.170 if I took one of the ones from A[br]and B-- so let me just go ahead 0:09:51.170,0:09:53.030 and circle that--[br]if I just took A. 0:09:53.030,0:09:55.780 If I took one of the ones from[br]A and B and one of the ones 0:09:55.780,0:09:58.000 from C and D, and[br]I'll just take C. Then 0:09:58.000,0:10:00.930 A and C are diastereomers[br]of each other. 0:10:00.930,0:10:04.910 They are non-superimposable,[br]non-mirror images 0:10:04.910,0:10:05.570 of each other. 0:10:05.570,0:10:07.750 So those are enantiomers[br]and diastereomers, 0:10:07.750,0:10:11.349 to review what we covered[br]in an earlier video. 0:10:11.349,0:10:13.390 Let's do one more thing[br]with Fischer projections. 0:10:13.390,0:10:16.270 Let's assign absolute[br]configurations 0:10:16.270,0:10:18.860 to one of the stereoisomers. 0:10:18.860,0:10:20.780 So let's just choose[br]the first one, A. 0:10:20.780,0:10:23.030 So we've been talking[br]about A. And let's go ahead 0:10:23.030,0:10:24.930 and redraw it really fast. 0:10:24.930,0:10:29.410 And let's see how can we figure[br]out the absolute configuration 0:10:29.410,0:10:34.357 at my chirality centers[br]from a Fischer projection. 0:10:34.357,0:10:36.440 So it just makes a little[br]bit trickier than usual. 0:10:36.440,0:10:38.330 So here I have my[br]Fischer projection. 0:10:38.330,0:10:40.250 And your aldehyde's[br]going to get a 1, 0:10:40.250,0:10:44.232 and then 2, 3, 4 in terms of[br]numbering your carbon chain. 0:10:44.232,0:10:46.190 I want to figure out the[br]absolute configuration 0:10:46.190,0:10:47.650 at carbon 2 here. 0:10:47.650,0:10:49.930 So at carbon 2, what do I have? 0:10:49.930,0:10:52.060 I know a Fischer[br]projection tells me 0:10:52.060,0:10:55.760 that if it's a horizontal line,[br]everything is coming out at me. 0:10:55.760,0:10:57.430 So my OH is coming out at me. 0:10:57.430,0:10:59.950 And my hydrogen is[br]coming out at me. 0:10:59.950,0:11:03.620 Let's go back up here and stare[br]down that carbon 2 chirality 0:11:03.620,0:11:04.120 center. 0:11:04.120,0:11:06.760 And let's see what we would[br]actually see if we do that. 0:11:06.760,0:11:09.390 So here is carbon 2 right here. 0:11:09.390,0:11:12.640 I'm going to stare down[br]right here this time. 0:11:12.640,0:11:15.070 So I have my OH[br]coming out at me, 0:11:15.070,0:11:17.240 my hydrogen coming out at me. 0:11:17.240,0:11:19.280 That makes this[br]bond and this bond 0:11:19.280,0:11:22.030 to actually go away[br]from me in space. 0:11:22.030,0:11:24.050 So the aldehyde is[br]going to go away 0:11:24.050,0:11:27.010 from me in space like that. 0:11:27.010,0:11:29.629 So I'm going to go ahead[br]and draw my aldehyde. 0:11:29.629,0:11:31.920 Now, I'm actually going to[br]go ahead and show the carbon 0:11:31.920,0:11:33.140 bond to one hydrogen. 0:11:33.140,0:11:35.519 I know the carbon's double[br]bonded to an oxygen, 0:11:35.519,0:11:36.810 so I'm going to go and do that. 0:11:36.810,0:11:38.893 That was that trick we[br]learned in an earlier video 0:11:38.893,0:11:40.490 for assigning absolute[br]configuration. 0:11:40.490,0:11:41.948 And then the rest[br]of the molecule's 0:11:41.948,0:11:43.370 actually going down in space. 0:11:43.370,0:11:46.290 So this would be a carbon[br]here bonded to a hydrogen. 0:11:46.290,0:11:48.950 And this carbon is bonded[br]to an oxygen and a carbon. 0:11:48.950,0:11:50.690 So what is the[br]absolute configuration 0:11:50.690,0:11:51.720 of this carbon here? 0:11:51.720,0:11:56.990 Well, if I think about this[br]is my chirality center, 0:11:56.990,0:11:59.210 what are the atoms directly[br]attached to that carbon? 0:11:59.210,0:12:01.690 Well, I have a hydrogen,[br]a carbon, an oxygen, 0:12:01.690,0:12:02.320 and a carbon. 0:12:02.320,0:12:06.670 Well, immediately I know that[br]my oxygen is going to win. 0:12:06.670,0:12:09.980 So I can go ahead and assign[br]a number 1 to my oxygen right 0:12:09.980,0:12:10.650 here. 0:12:10.650,0:12:13.070 And then I think about[br]what's next priority. 0:12:13.070,0:12:15.800 Well, it would be[br]carbon versus carbon. 0:12:15.800,0:12:19.450 So at the top, I have[br]oxygen, oxygen, hydrogen. 0:12:19.450,0:12:22.410 The bottom carbon, I have[br]oxygen, carbon, hydrogen. 0:12:22.410,0:12:24.080 So we saw in an[br]earlier video, you 0:12:24.080,0:12:25.455 go for first point[br]of difference. 0:12:25.455,0:12:27.750 So oxygen versus[br]oxygen, no one wins. 0:12:27.750,0:12:30.280 Then I go oxygen versus[br]carbon, and oxygen wins. 0:12:30.280,0:12:32.160 So this would get[br]a number 2 up here. 0:12:32.160,0:12:34.430 And then this would get a[br]number 3 for my substituent. 0:12:34.430,0:12:36.380 And my hydrogen[br]would get a number 4. 0:12:36.380,0:12:38.340 So I'm going around this way. 0:12:38.340,0:12:42.500 I am going around this way,[br]if I ignore my hydrogen. 0:12:42.500,0:12:44.460 So I'm going counterclockwise. 0:12:44.460,0:12:48.400 So it looks like it's S.[br]But remember, the hydrogen 0:12:48.400,0:12:50.070 is actually coming out at me. 0:12:50.070,0:12:53.229 So in the little trick I showed[br]you in the earlier video, 0:12:53.229,0:12:55.520 if the hydrogen is coming[br]out at me, all you have to do 0:12:55.520,0:12:56.560 is reverse it. 0:12:56.560,0:13:00.000 So it looks like it's S, but[br]since the hydrogen's coming out 0:13:00.000,0:13:02.710 at, me, I can go ahead[br]and say with certainty 0:13:02.710,0:13:05.560 that it is R at that[br]chirality center. 0:13:05.560,0:13:09.730 So at carbon 2, at[br]this carbon, it is R. 0:13:09.730,0:13:13.190 So you can do the same thing[br]with the chirality center 0:13:13.190,0:13:14.540 at the third position. 0:13:14.540,0:13:17.130 So you could do the same[br]thing with this one. 0:13:17.130,0:13:20.380 And if you do that, you[br]will find that it is also R. 0:13:20.380,0:13:23.090 So you could go ahead and[br]say for this carbohydrate, 0:13:23.090,0:13:27.730 it is R at carbon 2,[br]and it is R at carbon 3. 0:13:27.730,0:13:29.840 So it is 2R, 3R. 0:13:29.840,0:13:32.140 And there's a 2R,[br]3R stereoisomer. 0:13:32.140,0:13:35.930 And you could do that for[br]all four of the stereoisomers 0:13:35.930,0:13:37.750 that we drew for[br]this carbohydrate. 0:13:37.750,0:13:40.580 And you could then compare[br]enantiomers and diastereomers 0:13:40.580,0:13:41.670 that way, as well. 0:13:41.670,0:13:44.570 So that's a quick summary[br]of Fischer projections. 0:13:44.570,0:13:45.200 Practice. 0:13:45.200,0:13:47.930 And use your molecular[br]model set to help you 0:13:47.930,0:13:50.530 with the visualization aspect. 0:13:50.530,0:13:51.296