## FizzBuzz - Web Development

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Okay, how did you do? Spectacularly well, I hope. Lets
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go over the solution. Okay, so my solution looks something
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like this. First we have an ordered list at the
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top and bottom. You know? Opening and closing. And then
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we have a for loop for going over the range from 1 to n plus 1 and then we say,
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basically, if x is divisible, and we can use the
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mod operator to determine if something is divisible. Mod basically
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says, it gives you, it gives you the remember. So, x
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is divided by 15, what is the remainder. If that, If
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that's zero that means x is divisible by both 3 and
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5 we print FizzBuzz. If it's divisible by 3 we print Fizz,
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if it's divisible by 5 we print Buzz, else we just
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print x. And we have our end if and our end for.
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Okay, not too bad huh? Now there's lots of ways of,
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you know, if you want to minimize the logic done here but
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that's not really what I'm trying to look for right here. I
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just want to see if you can actually use your for statements
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and your if statements and your
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variable substitution. And your variable substitution
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to make a quick little template. So if you got that, nicely done.
タイトル：
FizzBuzz - Web Development

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Video Language:
English
Team:
Udacity
プロジェクト：
CS253 - Web Development
Duration:
01:04
 Udacity Robot edited 英語(米国) subtitles for 08-18 FizzBuzz Udacity Robot edited 英語(米国) subtitles for 08-18 FizzBuzz Cogi-Admin edited 英語(米国) subtitles for 08-18 FizzBuzz

# English subtitles

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