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Joint Variation Practice 2 - Visualizing Algebra

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    it turns out the value of X would be 84 when Y is & and Z is 1. Nice work if you
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    figured that one out. We know the values for X1, Y1, and Z1 so we plug those in
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    here. We are looking for the X value when Y is 7 and Z is 1, so we plug in 7 and
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    1 in these positions. We can think of these numbers as being the second case
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    We're looking for x 2, which is x, and we know the second y value is 7, and the
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    second z value is 1. We use these lists to make our substitution. We simplify
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    this right hand side to get 5 42nds. Next we multiply both sides of the equation
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    by the LCD, 42x. Essentially, this is the same as cross-multiplying. So we get
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    5x on the right and 420 on the left. We divide both sides by 5 to get x is equal
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    to 84.
Cím:
Joint Variation Practice 2 - Visualizing Algebra
Video Language:
English
Team:
Udacity
Projekt:
MA006 - Visualizing Algebra
Duration:
0:50
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