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www.mathcentre.ac.uk/.../8.4%20Quotient%20rule.mp4

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    Functions often come defined
    as quotients, so.
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    Let's just write that word down
    quotients so functions come
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    defined. This quotients by,
    which we mean we have one
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    function cause X, let's say
    divided by another function,
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    cause X divided by X squared.
    What we do is we identify that
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    as one function you divided by
    another function V.
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    This then gives us yet another
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    result. Another formula that we
    need to be able to remember.
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    This one goes VU
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    by TX. Minus
    you DV by
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    DX all over
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    V squared. Now it looks very
    complicated formula, but it's
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    not really you just have to
    remember the minus side and I
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    must say the way that I always
    remember it is if anything is
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    going to go wrong with anything,
    it's going to be what's in the
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    denominator. So when we do the
    derivative. We're going to have
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    to have a minus sign.
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    Let's have a look how this
    formula is going to work with
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    this particular example.
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    So let's have a
    look at this example.
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    Y equals cause X
    over X squared, and
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    we've identified this as
    being you over VU
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    divided by V.
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    So you is
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    cause X. And
    the is X squared. We
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    can write down their
    derivatives. Do you buy DX
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    is minus sign X and
    DV by DX is 2
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    X? Quote the
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    formula. DY by the X
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    is. VU
    by DX
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    minus UDVX
    all over
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    the squared.
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    Again, we're quoting the formula
    every time, because that way we
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    get to remember it. We get to
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    know it. Equals and now we can
    plug in the various bits that
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    we've got. So V will be X
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    squared. Times by DU by
    DX. So that's times by minus
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    sign X. Minus because of the
    minus that there is in the
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    formula and then we want you
    which is convex.
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    Times by and we want DV by
    DX, which is 2 X.
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    And then all over.
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    The squared, and in this case V
    is X squared, so that's X
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    squared all squared.
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    Now again, this doesn't look
    very nice. It needs tidying up.
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    We need to gather things
    together, so if I turn over the
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    page, write this expression
    again at the top of the page.
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    Writing that down
    again DYX is
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    equal 2.
    X squared times
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    minus sign X
    minus cause X.
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    Times 2X all
    over X squared
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    squared. OK, we need to
    simplify this look again for the
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    common factor, and there's an X
    there in the X. Squared is a
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    minus sign there a minus sign
    there and an X there. So from
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    each term we can take out the
    minus sign and the X and on top
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    that will leave. As with X Sign
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    X. Plus most be a plus
    now because we've taken the
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    minus sign out plus and here
    we've got 2.
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    Kohl's X left.
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    All over and now X squared all
    squared is X to the power 4.
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    Having done that, we can see
    that there's now a factor of X
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    common to both the top, the
    numerator and to the bottom the
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    denominator. So we can divide
    the top and the bottom by X in
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    order to simplify it, so the
    minus sign stays minus X.
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    Sign X +2
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    cause X. All
    over X cubed and we can leave
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    it like that.
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    Simplified in that way.
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    And that's useful, because now
    if we wanted to, we could go on
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    and put it equal to 0 and we
    could sort out Maxima and minima
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    and all that kind of thing. So
    it's always helpful to try and
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    rearrange these expressions,
    particularly to get the top in a
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    simplified form. Notice though,
    that we didn't cancel any of
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    these axes in here. That part of
    the sine X. That part of the
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    variables. You can't just go
    canceling them out. You can only
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    cancel those out, which are
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    common factors. Let's take a
    second example. This time. Let's
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    take it one that's just got
    polynomial functions of accent,
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    so we've got X squared +6
    all over 2X.
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    Minus 7, just polynomials now
    causes no signs etc, so this is
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    a U over VA quotient again.
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    Let's line this one up. You
    equals X squared, and so do
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    you find the X will be
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    2X. The is 2X
    minus Seven, and so DV
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    by DX is just two.
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    Quote the formula Y
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    equals V. You buy
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    TX. Minus
    UDVX
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    All over the squared.
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    Now we quoted the formula. We
    now in a position to be able to
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    substitute in the various pieces
    that we need so.
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    Why by
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    the X?
    Is equal 2.
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    Now this is VDU by DX
    so that's 2X minus 7.
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    Times by du by DX,
    which is 2 X.
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    Minus. U which was
    X squared plus six times divided
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    by DX, which was just two
    and this is all over the
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    square so it's all over 2X
    minus 7 squared.
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    Now again we need to think about
    this one. We need to simplify
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    it. We need to get together the
    various terms and if we look,
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    there's a common factor of two
    there and there so we can take
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    that two out as a common factor
    and put it at the front. So we
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    have two. Then when we multiply
    out with X times by two X, that
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    gives us two X squared.
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    X times by 7 gives us minus
    Seven X. Then we have minus
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    this, so it's minus X squared
    minus six. Close the bracket.
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    All over 2X
    minus Seven or
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    square. Keep the two outside and
    let's simplify the terms inside.
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    X squared Minus Seven
    X minus 6.
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    All over 2X minus Seven
    or squared and that's
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    now informed. We need to
    go on and do something
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    else with it we can do.
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    3rd example that I'd like to
    do with you is one where
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    we're going to use this
    result in order to help us
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    establish something new.
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    Now we're going to use this
    result to help us prove another
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    result. So let's begin with Y
    equals 10 X. It's a standard
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    function, so we want to be able
    to differentiate it in a
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    standard way. We want to result.
    We can use and just keep on
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    using it. So we've got to begin
    with the definition of Tan X Tan
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    X is defined as being sign X
    over cause X, and of course
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    that's now a quotient, isn't it?
    That's now you over V, because
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    we've been. Able to identify the
    you over V. Then we can have U
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    equals sign X and so do you buy
    the X will be cause X.
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    We've got the equals cause X
    and so DV by the X
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    will be minus.
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    Sign X. Lots of causes and
    signs about, so we need to be
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    very, very careful when we do
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    the substitution. Close quote
    the formula DY by
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    the X is VU
    by DX minus UDVX
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    all over V squared.
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    And we're going to make this
    substitution, so let's just work
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    our way through that.
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    The why by DX.
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    Will be. Now it's VDU
    by the X so V was
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    cause X.
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    You was sign X, so
    its derivative is caused X.
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    Minus from the formula.
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    You divvy by DX. Now
    you was sign X.
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    And DV by the X will V was cause
    exo DV by the X is minus sign X.
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    Oh, over.
    The squared and V was cause X,
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    so that's all over Cos squared
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    X. We now need to simplify the
    top so we have cause X times by
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    cause X, so that's cost squared
    X. We have a minus and minus
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    sign, so that's going to give us
    a plus and we've sign X times by
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    cynex, so we've signed squared
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    X. All over cause
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    squared X. Equals.
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    Now this is a standard result,
    well known result cost squared
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    plus sign squared is always
    equal to 1 cost squared X plus
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    sign squared. X is one, so
    that's one over cause squared X
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    and of course we have another
    way of writing one over cost
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    squared. One over kozaks we
    usually write as being sack X,
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    so one over cost squared X. We
    would write as SEK squared X.
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    And so that's how we
    differentiate tab. And now we've
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    got a standard result that the
    derivative of tangent is sex
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    squared X. We can simply quote
    that and use it anytime that we
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    want to. We take one more
    example of using this in the
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    same sort of way.
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    Let's take the function Y
    equals second X.
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    Now we know the definition of
    Psychics. It's one over cause X.
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    One of the ways of doing this
    now is to realize that this is a
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    quotient. It's AU over V.
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    Having identified those, we
    can say you equals 1, and so
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    do you buy. The X will be
    equal to. Now one is just a
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    constant, so remember a
    constant is about rate of
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    derivative is about rate of
    change. So if we
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    differentiate something
    which is constant rate of
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    change must be 0.
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    The is cause X and
    so DV by the X
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    will be minus sign X.
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    And again, our
    formula is DY by
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    X is equal to.
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    The DU by The
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    X. Minus UDV
    by the X all
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    over V squared.
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    So we're going to make the
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    substitution now. This is going
    to change things slightly if do
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    you buy the Axis zero when we
    start multiplying by zero sum of
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    things may happen so.
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    DY by DX is VDU
    by DX now remember V
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    was cause X times do
    you buy DX that was
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    zero because you was one.
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    Minus U, that's one.
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    Times by DV by DX now remember V
    was cause X and so its
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    derivative is minus sign X and
    then all over V squared, which
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    is cost squared X. So what we've
    got cause X times by zero is
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    zero. Anything times by zero is
    0 minus. Minus gives us a plus,
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    and so we've got sine X over
    cause squared X.
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    Looks looks like it might be
    something else, and remember
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    that we've just seen that tan
    is sign over cars, so I
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    can write this as one over
    cause X times sign X over
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    cause X here I've got one
    over cause is sex X.
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    Times sign over cause which is
    10 X so I end up with the
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    result that the derivative of
    sex is sex tinix.
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    So. Anytime we want to use the
    derivative of sex, we can do so.
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    All we do is we just write it
    straight down sex tanks and
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    that's it. We don't have to work
    it all out again.
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    And that's the end of Quotients.
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www.mathcentre.ac.uk/.../8.4%20Quotient%20rule.mp4
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