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www.mathcentre.ac.uk/.../Hyperbolic%20functions.mp4

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    In this video, we'll define
    the hyperbolic functions
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    hyperbolic sign, hyperbolic
    cosine and Hyperbolic Tangent.
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    We'll define hyperbolic cosine
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    first. We write hyperbolic
    cosine like this.
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    We pronounce
    it Cosh
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    X. And it's defined
    using the exponential functions
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    like this. Cos X equals.
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    Each the X Plus E to the
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    minus X. All divided by
    two.
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    Hyperbolic sign is
    written like this.
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    There are two
    ways of pronouncing
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    hyperbolic sign. In this video
    I'll call it shine, but you will
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    come across some people who call
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    it's inch. And Shine X is
    defined with the exponential
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    function, again like this.
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    We have each the X minus this
    time, each the minus X all
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    divided by two.
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    Now we can use our knowledge of
    the graphs of E to the X
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    to workout the graphs of Shine X
    and Koch X.
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    Here I've got some graphs of E
    to the X over 2 and E to the
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    minus X over 2.
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    First, we'll workout what
    cautious 0 is.
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    A quickly remind you that
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    quarterbacks. Is each the X plus
    E to the minus X over 2?
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    So Koch of
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    0. Is eat 0,
    which is one.
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    Plus E to the zero again, which
    is one all divided by two.
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    Which is 2 over 2, which is one.
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    So we can Mark Koch
    0 onto a graph here.
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    Now we can workout. What happens
    is X gets big.
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    We can split up how we write
    quash X into this form. We have
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    each the X over 2 plus E
    to the minus X over 2.
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    Now we already have the graphs
    of E to the X over 2 and E to
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    the minus X over 2 here, and we
    can see that as X gets big.
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    East the X over 2 gets very very
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    big. But each of the minus X
    over 2 gets very very small.
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    So as X gets bigger, the second
    part of the sum.
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    Gets very very close to 0.
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    So the whole thing.
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    Gets very very close to
    just eat the X.
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    Over 2. So
    now we can rule
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    that side of the
    graph.
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    I'll just turn around the graph
    so I can actually draw it.
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    Now remember that be'cause each
    the minus X over 2.
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    Is always bigger than zero even
    though it gets very very small.
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    Call shacks will always stay
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    above. The graph of each of
    the axe over 2.
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    The grass get closer
    together as X gets big, but
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    Cosh X must always stay
    above E to the X over 2.
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    Now we'll see what happens when
    ex gets large and negative.
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    Now when
    ex gets
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    larger negative.
    We can see that each the X
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    over 2 gets very very small,
    but E to the minus X over 2
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    gets very very big.
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    So writing Cosh X again.
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    As each the X over 2 plus
    E to the minus X over 2.
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    We can see that the first part
    of the sum, this time gets very
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    very small. And the second part
    of the sum gets very very big.
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    So the whole thing.
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    As X gets larger, negative will
    get closer and closer to eat.
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    The minus X over 2.
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    So we can draw in that side
    of the graph now.
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    And remember again.
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    That E to the X over 2 even
    though it's getting very, very
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    small, will always be bigger
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    than 0. So the graph will always
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    stay above. East the minus X
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    over 2. As X gets more negative,
    the graphs get closer together.
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    But the graph will always stay
    above each the minus X over 2.
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    So here is a graph.
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    Of Cos X.
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    Now you can see that this graph
    is symmetric about the Y axis.
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    And that tells us that cause
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    checks. Is always equal
    to Koch of minus
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    X?
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    Now let's deal with the
    graph was trying X.
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    This time to help me. I've got a
    graph of each of the X over 2.
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    And minus E to the minus
    X over 2.
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    Let's see what happens
    when X equals 0.
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    I'll just remind
    you that Shine X.
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    Is each the X minus E to
    the minus X over 2?
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    So shine. Of
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    0. Is each zero?
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    Which is one.
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    Minus Y to 0, which is one.
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    All over 2 so that zero over
    2 which is 0.
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    Right, so we can plot that
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    point. Onto a
    graph at 00.
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    Now we'll see what happens
    as X gets large.
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    Like before, we can split up the
    way we write Shine X.
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    So we write Shine X.
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    As each the X over
    2 minus E to the
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    minus X over 2.
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    Now, using the same logic as we
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    did before. And remembering what
    the graphs of E to the X&E to
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    the minus X over 2 looked like.
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    We can see that.
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    The first part of the some here.
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    Gets very, very big as X
    gets large.
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    But the second part of the sum.
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    Gets very, very small as X gets
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    large. So again.
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    Floor Jacks.
    The whole of Shine
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    X becomes closer and
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    closer. To eat the
    X over 2.
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    So now we
    can draw in
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    that half of
    the graph.
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    No,
    just
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    this
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    time.
    The graph will stay below each
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    the X over 2.
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    And that's because we're taking
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    away. E to the minus X over 2.
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    Now let's see what happens when
    ex gets larger negative.
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    Again, just so you can
    see what's happening, I'll write
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    up are split up form
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    shine X. I
    remember as
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    ex got
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    larger negative. Each of
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    the X. Got very very small.
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    For the first part of the son
    gets very very small.
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    Eat the minus X over 2.
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    Got very very big.
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    So this whole thing as X gets
    larger, negative gets closer and
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    closer to. Just the second bit
    of the sum, because the first
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    bit is getting closer to 0.
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    So for large negative.
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    X.
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    Sean X. Gets
    very, very close to.
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    Minus each the minus X.
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    Over 2.
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    So we can draw the second bit of
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    a graph and now. Now again,
    the graph must
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    stay above minus
    E to the
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    minus X over
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    2. Be'cause each the X over
    2 is never 0 even though it gets
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    very very small.
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    So that adds a bit on to minus E
    to the minus X over 2. It keeps
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    the graph above it.
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    Now you know tist that shine X
    for LG X is close to eat the X
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    over 2. And Koch X also remember
    was close to E to the X over 2
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    for LG X. So that must mean.
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    Floor Jacks.
    Khashab
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    X. And Shine
    X are very close together.
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    And we can see that
    if I show you a
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    graph of Cynex and koshek
    spotted together.
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    Got a slightly different scale
    this time so it looks a bit
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    wider. But there is caution X.
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    And they're showing X, which
    gets very, very close to quash X
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    as X gets large.
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    Now we'll define
    hyperbolic tangent.
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    We can define hyperbolic tangent
    in terms of shine and Koch.
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    We write Hyperbolic Tangent.
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    Like this? And again, there are
    two possible pronunciations for
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    this. Some people call it touch.
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    But I'm in this video,
    we'll call it fan.
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    And we define it to be.
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    Sean X.
    Over Cosh X.
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    And again, there's an
    exponential function definition
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    which we can work out by looking
    at this definition.
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    Because this is Sean X which is
    E to the X minus E to the
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    minus X over 2.
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    Divided by Cosh X, which is E to
    the X Plus E to the minus X over
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    2. And that's when you work it
    out is if the X minus E to the
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    minus X all divided by.
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    Each the X Plus E
    to the minus X.
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    Now this thing doesn't look very
    useful for working out the
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    graph. It's a bit complicated,
    so this time will use the graph
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    of shine and Koch to workout the
    graphs of ban.
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    Now here I've got
    a set of axes
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    which I'll use to
    draw down onto.
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    I've got an asymptotes here at Y
    equals 1 and one at White was
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    minus one and you'll see why in
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    a minute. I remember
    that 4X large.
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    We saw that
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    Cosh X. Was
    very, very close.
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    To Shine X.
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    So that must mean
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    that. Shine X.
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    Over Cosh
    X.
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    Must be very close to one.
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    So as X
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    gets large. We should expect
    Linix to get very close to one.
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    Now for large negative X.
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    We
    saw
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    that.
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    Call shacks Was very close
    to eat a minus X.
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    Over 2.
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    And Shine X.
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    Was very close to minus E to the
    minus X over 2.
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    So you can see here that Shine
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    X. Is very very close to minus
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    Cosh X. So that must
    mean that Shine X.
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    Over Cosh X.
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    Is very very close
    to minus one.
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    So as X gets larger, negative.
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    We should expect the graph to
    get very very close to minus
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    one. Now just to finish off,
    will see what happens when X
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    equals 0. So
    for X
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    equals 0.
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    Thanks.
    Which is shine.
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    Over Cos X.
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    Will be well shine of X.
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    Was zero, so that would be 0.
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    Call Shabaks was one.
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    So fun of X when X equals
    0 is just zero.
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    Now, putting these three bits of
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    information together. We can
    plot 00 on that.
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    And his ex got large.
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    Thanks, got close to one so we
    can see this thing getting
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    closer to one.
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    And his ex got large and
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    negative. Thanks, got close to
    minus one so we can draw this.
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    Going down toward minus one.
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    But remember that.
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    These never actually reach
    one or minus one. They just
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    get very very close to them
    as X gets large reserves gets
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    more negative.
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    Also notice that.
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    Fun. Of
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    ex. Is equal to
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    minus fan? Of minus X.
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    Now hyperbolic functions
    has my densities
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    which are very
    similar to trig
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    identities, but not
    quite the same.
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    In this video I'll show you and
    prove for you, too, and then
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    I'll show you some more at the
    end, which you control yourself.
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    The first one will prove is this
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    one. It's caution.
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    X squared
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    minus shine. X
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    squared Equals 1.
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    Not prove this will substitute
    in the exponential definitions
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    for Koch and shine.
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    So we have the costs. X was each
    the X Plus E to the minus X over
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    2, and we want that all squared.
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    We take away shine X squared,
    which was E to the X minus E to
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    the minus X over 2 all squared.
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    Now notice that in both bits of
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    this. We have the same
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    denominator squared. So we can
    take that out of the factor.
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    So we have that.
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    As a quarter.
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    Of the numerator squared.
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    So we have each of the X Plus E
    to the minus X squared.
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    Minus eat the AX minus E
    to the minus X squared.
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    Now we want to expand out
    these squared brackets.
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    So that is going to be.
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    Well, these brackets.
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    Are going to be each the X times
    E to the X which is E to the 2X.
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    And because each the X Times E
    to the minus X is one.
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    And we get that happening twice.
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    We get a plus two here.
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    And each the minus X Times E to
    the minus X.
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    Is each the minus 2X?
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    And I will take away this
    bracket squared which working
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    out before we can see is.
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    Each the two weeks again.
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    And this time we get a minus two
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    here. And we get.
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    Plus, if the minus 2X.
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    Now we can remove these
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    inner brackets. And we get a
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    quarter. Of.
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    Just take out the first brackets
    first, E to the two X +2, plus E
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    to the minus 2X.
  • 20:45 - 20:47
    Put a minus here, so that's
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    minus. Each the 2X.
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    +2. Minus.
    E to the minus 2X.
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    And of course, a lot of things
    that are going to cancel here.
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    We have E to the two X minus
    either 2X, so these go.
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    We have plus E to the minus
    two X here and minus it again
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    there, so they go.
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    And then we just have 2 + 2, so
    the whole thing turns out to be
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    1/4 of 2 + 2, which is 4.
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    Which is one.
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    So there we have the proof
    that cause squared X minus
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    sign squared X, which is
    all that is equal to 1.
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    And one more density or
    proof you now is this
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    one. It's shine 2X.
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    Equal to two.
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    Sean X. Call
    Josh X.
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    Now with this one, I think it's
    easier to start with the right
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    hand side, so will do that
    again. Will a substitute in the
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    exponential definitions to the
    right hand side.
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    So 2.
    Sean
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    X. Cosh
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    X. Is equal to.
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    Two lots of.
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    Each 3X minus each the minus X
    over 2 times caution X which was
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    E to the X Plus E to
    the minus X over 2.
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    Now you can see the two councils
    with one of these denominators,
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    so will cancel those.
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    And take out this half as a
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    factor. So now
    we have 1/2.
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    Each of the X minus E to the
    minus X Times E to the X Plus
  • 23:10 - 23:12
    E to the minus X.
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    And if we just multiply out the
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    brackets. We get a half.
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    Get each the X Times E to the X,
    which is each the two acts.
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    Each the X Times Plus E to the
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    minus X. Which is plus one.
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    Minus E to the minus X times Y
    to the X, which is minus one.
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    And finally, minus each the
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    minus 2X. So obviously
    these ones cancel.
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    And we get this bracket here,
    which was E to the two
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    X minus. Eat the minus 2X.
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    All divided by two.
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    And that is the definition of
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    shine 2X. So that's
    the second identity proved.
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    Now here is more identity's
    which you can prove yourself.
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    The first one
    is Koch 2X.
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    Is equal to.
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    Call shacks
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    squared.
    Plus
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    Shine X squared.
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    We also have.
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    Shine of X
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    Plus Y.
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    Equals.
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    Shine X.
    Gosh why?
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    Plus Shine
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    Y. Koch
    X.
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    And also for Koch.
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    X plus Y.
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    We have cautious.
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    X. Call
    Shuai Plus Shine
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    X. Shine
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    Y. And
  • 25:38 - 25:42
    two more.
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    Gosh. X over
    2.
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    All squared. Is 1
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    plus. Cosh X all
    divided by two.
  • 25:58 - 26:01
    And finish off shine.
  • 26:02 - 26:04
    X over 2.
  • 26:04 - 26:12
    All squared. Is
    Cosh X minus one
  • 26:12 - 26:15
    all divided by two?
  • 26:16 - 26:20
    Now you can see how similar
    these are to trig identities.
  • 26:21 - 26:24
    And in fact, the hyperbolic
    functions and triggered entities
  • 26:24 - 26:26
    are very closely related.
  • 26:27 - 26:30
    And you can learn more about
    that if you go and study complex
  • 26:30 - 26:37
    numbers. And before we
    finish, we look at some
  • 26:37 - 26:43
    other functions which are
    related to hyperbolic functions.
  • 26:44 - 26:45
    Firstly, some notation.
  • 26:46 - 26:48
    You've already seen me use
  • 26:48 - 26:55
    notation like. Sean X
    squared, which means.
  • 26:55 - 26:59
    The whole of Shine X squared.
  • 27:00 - 27:02
    Just remember that if you see
  • 27:02 - 27:10
    something like. Sean X with a
    minus one there that is not
  • 27:10 - 27:12
    equal to 1.
  • 27:12 - 27:16
    Over Shine X.
  • 27:16 - 27:20
    This refers to the inverse
    function of shine.
  • 27:21 - 27:28
    If you remember that if we
    have a function F.
  • 27:29 - 27:32
    F minus one the inverse function
    works like this.
  • 27:33 - 27:40
    You have F minus one.
    The inverse function of X
  • 27:40 - 27:47
    gives you this thing why
    where F of Y is
  • 27:47 - 27:49
    equal to X.
  • 27:50 - 27:51
    And the same way.
  • 27:53 - 27:56
    Shine with the minus one there.
  • 27:57 - 28:00
    Of X gives You Y.
  • 28:02 - 28:08
    Will shine of why was
    equal to X?
  • 28:09 - 28:13
    We can also define inverse
    functions for caution than.
  • 28:14 - 28:16
    But for these we have to
    restrict the domains of
  • 28:16 - 28:16
    the function.
  • 28:17 - 28:24
    For inverse Cosh, Cosh the minus
    one of X, we need to have.
  • 28:24 - 28:27
    X greater than or equal to 1.
  • 28:28 - 28:34
    And for the inverse of
    fan of X.
  • 28:34 - 28:41
    We need X to be greater than
    minus one and less than one.
  • 28:44 - 28:50
    Some other functions you
    might come across other
  • 28:50 - 28:52
    reciprocal functions.
  • 28:54 - 28:56
    These are such.
  • 28:58 - 29:06
    X. Which is defined
    to be one over Cosh of X.
  • 29:06 - 29:08
    There are two more of these.
  • 29:09 - 29:15
    This Kosach
    Of X, which
  • 29:15 - 29:20
    is one over
    shine of X.
  • 29:21 - 29:26
    And finally, there's
    cough X.
  • 29:29 - 29:33
    Which is one over fan.
Title:
www.mathcentre.ac.uk/.../Hyperbolic%20functions.mp4
Video Language:
English

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