12-19 Cancer_Example_2_Solution

• 0:00 - 0:06
And the answer is 0.0333 or a 1/3 and now we're going to
• 0:06 - 0:10
apply the entire arsenal of inference we just learned about.
• 0:10 - 0:18
The joint probability of cancer and positive is 0.1 * 0.9. That's the joint that's not normalized.
• 0:18 - 0:23
So let's normalize it and we normalize it by the sum of the joint
• 0:23 - 0:26
for cancer and the joint for non-cancer.
• 0:26 - 0:33
Joint for cancer we just computed but the joint for non-cancer assumes the opposite prior 1-0.1
• 0:33 - 0:37
and it applies the positive result of a non-cancer case.
• 0:37 - 0:41
Now because the specificity first is negative, we have to do the
• 0:41 - 0:46
same trick as before and multiply it with 1-0.8.
• 0:46 - 1:00
When you worked this out, you find this to be 0 to 0.9 divided 0 to 0.9 + 0.9 * 0.2 that is 0.18
• 1:00 -
So if you put these all of this together, you get exactly a third.
Title:
12-19 Cancer_Example_2_Solution
Description:

12-19 Cancer_Example_2_Solution

more » « less
Video Language:
English
Team:
Udacity
Project:
ST101 - Intro to Statistics
Duration:
01:05
 Udacity Robot edited English subtitles for 12-19 Cancer Example 2 Solution Udacity Robot edited English subtitles for 12-19 Cancer Example 2 Solution Udacity Robot edited English subtitles for 12-19 Cancer Example 2 Solution Amara Bot added a translation

English subtitles

Incomplete

Revisions Compare revisions

• API
Udacity Robot
• API
Udacity Robot
• API
Udacity Robot
• Amara Bot