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02-46 Thwarting Dictionary Attacks Solution

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    [Evans] Now the answer is the third one--
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    that it makes it about 4000 times harder.
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    So to compute a dictionary that would be effective against all the different salts,
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    the attacker really needs to pre-compute that dictionary for all the different salt values
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    to be able to look for passwords that match.
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    So salting adds a lot of value for very little cost.
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    We just need some extra bits that don't need to be kept secret
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    that are stored in our password file.
Title:
02-46 Thwarting Dictionary Attacks Solution
Description:

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Team:
Udacity
Project:
CS387 - Applied Cryptography
Duration:
0:26
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