﻿[Script Info] Title: [Events] Format: Layer, Start, End, Style, Name, MarginL, MarginR, MarginV, Effect, Text Dialogue: 0,0:00:00.00,0:00:03.00,Default,,0000,0000,0000,,For this problem, imagine that we have a skier on this really steep slope Dialogue: 0,0:00:03.00,0:00:07.00,Default,,0000,0000,0000,,that's 90 meters tall and he comes to this ramp of height 10 meters Dialogue: 0,0:00:07.00,0:00:09.00,Default,,0000,0000,0000,,that makes an angle α with the ground. Dialogue: 0,0:00:09.00,0:00:15.00,Default,,0000,0000,0000,,I want you to tell me using your knowledge of energy and two dimensional motion Dialogue: 0,0:00:15.00,0:00:20.00,Default,,0000,0000,0000,,how far away from the ramp will the skier land--what's this distance d? Dialogue: 0,0:00:20.00,0:00:25.00,Default,,0000,0000,0000,,Measured from where the skier lands to the bottom of the of ramp when he took off. Dialogue: 0,0:00:25.00,0:00:32.00,Default,,0000,0000,0000,,Put your answer here and use 30 degrees for α and use 10 m/s² for g Dialogue: 0,0:00:32.00,0:00:35.00,Default,,0000,0000,0000,,rather than 9.8 just so we're all in the same page. Dialogue: 0,0:00:35.00,0:00:39.00,Default,,0000,0000,0000,,Now, you may end up having to use the quadratic equation in this problem. Dialogue: 0,0:00:39.00,0:00:42.00,Default,,0000,0000,0000,,If you're out of practice with this or maybe you never learned it, Dialogue: 0,0:00:42.00,9:59:59.99,Default,,0000,0000,0000,,check for links in the description for help on how to use the quadratic equation to solve this problem.