1 00:00:03,080 --> 00:00:07,357 In this video I'm going to try to motivate the study of complex 2 00:00:07,357 --> 00:00:11,305 numbers by explaining how we can find the square root of a 3 00:00:11,305 --> 00:00:15,640 negative number. Before we do that, let's record some facts 4 00:00:15,640 --> 00:00:16,780 about real numbers. 5 00:00:17,630 --> 00:00:22,674 On the diagram here, I've drawn what we call a real number line. 6 00:00:23,580 --> 00:00:27,816 And every real number has its place on this line. Now I've 7 00:00:27,816 --> 00:00:32,052 marked the whole real numbers from minus nine up to plus nine, 8 00:00:32,052 --> 00:00:35,935 so all the positive numbers to the right hand side. The 9 00:00:35,935 --> 00:00:40,171 negative numbers are to the left hand side. Every real number has 10 00:00:40,171 --> 00:00:43,701 its place on this line, so the integers, positive integers, 11 00:00:43,701 --> 00:00:47,231 negative inches, integers are here. We could also put the 12 00:00:47,231 --> 00:00:51,114 fractions on as well. So for example the real number minus 13 00:00:51,114 --> 00:00:53,232 1/2 would lie somewhere in here. 14 00:00:54,890 --> 00:00:59,156 Decimal numbers, like 3.5 would be somewhere in there. 15 00:00:59,730 --> 00:01:03,342 And even numbers like pie with some, some place someone here as 16 00:01:03,342 --> 00:01:07,556 well. So as pie is going to be in there somewhere. So the point 17 00:01:07,556 --> 00:01:11,168 is that all real numbers have their place on this real number 18 00:01:11,168 --> 00:01:16,225 line. Let's look at what happens when we square any real number. 19 00:01:16,225 --> 00:01:19,775 Suppose we take the number 3 and we square it. 20 00:01:20,390 --> 00:01:26,851 When we square 3, remember we're multiplying it by itself, so 3 * 21 00:01:26,851 --> 00:01:29,336 3 the answer is 9. 22 00:01:31,150 --> 00:01:36,094 What about if we take the number minus three and square that? 23 00:01:36,640 --> 00:01:41,130 Again, when we square it, we multiplying the number by 24 00:01:41,130 --> 00:01:45,171 itself, so it's minus 3 multiplied by minus three. 25 00:01:45,180 --> 00:01:48,854 And here, if you recall that multiplying a negative number by 26 00:01:48,854 --> 00:01:51,860 a negative number yields a positive result, the answer 27 00:01:51,860 --> 00:01:55,200 minus three times minus three is plus 9 positive 9. 28 00:01:55,770 --> 00:02:00,150 Now the point I'm trying to make is, whenever you Square a 29 00:02:00,150 --> 00:02:04,530 number, be it a positive number or a negative number. The answer 30 00:02:04,530 --> 00:02:05,625 is never negative. 31 00:02:06,240 --> 00:02:09,170 In fact, unless the answer, unless the number we started 32 00:02:09,170 --> 00:02:12,686 with zero, the answer is always going to be positive. You can't 33 00:02:12,686 --> 00:02:15,323 get a negative answer by squaring a real number. 34 00:02:15,860 --> 00:02:18,149 Now, over the years, mathematicians found this 35 00:02:18,149 --> 00:02:21,746 shortcoming a problem and they decided that will try and work 36 00:02:21,746 --> 00:02:25,670 around that by introducing a new number, and we're going to give 37 00:02:25,670 --> 00:02:30,248 this new number at the symbol I, and I'm going to be a special 38 00:02:30,248 --> 00:02:33,845 number that has this property that when you square it, the 39 00:02:33,845 --> 00:02:35,153 answer is minus one. 40 00:02:36,230 --> 00:02:41,074 So I is a special number such that the square of I I squared 41 00:02:41,074 --> 00:02:45,226 is minus one. Now that clearly is a very special number because 42 00:02:45,226 --> 00:02:48,686 I've just explained that when you square any positive or 43 00:02:48,686 --> 00:02:52,146 negative real number, the answer can never be negative. So 44 00:02:52,146 --> 00:02:54,568 clearly this number I can't be a 45 00:02:54,568 --> 00:02:59,564 real number. What it is, it's an imaginary number. We say I is an 46 00:02:59,564 --> 00:03:04,052 imaginary number. Now that might seem rather strange. When you 47 00:03:04,052 --> 00:03:07,892 first meet, it's starting to deal with imaginary numbers, but 48 00:03:07,892 --> 00:03:12,500 it turns out that when we progress a little further and we 49 00:03:12,500 --> 00:03:16,340 do some calculations with this imaginary number, I lots of 50 00:03:16,340 --> 00:03:19,412 problems in engineering and physics and applied mathematics 51 00:03:19,412 --> 00:03:22,484 can be solved using this imaginary number I. 52 00:03:23,220 --> 00:03:26,904 Now using I, we can formally write down the square root of 53 00:03:26,904 --> 00:03:30,588 any negative number at all. So supposing we want to write down 54 00:03:30,588 --> 00:03:33,965 an expression for the square root of minus nine square root 55 00:03:33,965 --> 00:03:35,193 of a negative number. 56 00:03:35,920 --> 00:03:40,652 What we do is we write the minus nine in the following way. We 57 00:03:40,652 --> 00:03:43,018 write it as plus 9 multiplied by 58 00:03:43,018 --> 00:03:47,470 minus one. And then we split this product as follows. We 59 00:03:47,470 --> 00:03:49,710 split it as the square root of 60 00:03:49,710 --> 00:03:55,216 9. Multiplied by the square root of minus one. 61 00:03:55,220 --> 00:04:00,212 So the square root of 9. We do know the square root of 9 is 3 62 00:04:00,212 --> 00:04:04,580 and the square root of minus one is going to be I because I 63 00:04:04,580 --> 00:04:08,636 squared is minus one. So I is the square root of minus one. 64 00:04:08,940 --> 00:04:12,024 The words now we can formally write down the square root of 65 00:04:12,024 --> 00:04:13,566 minus nine is 3 times I. 66 00:04:14,750 --> 00:04:19,150 Let's give you another example. Suppose we wanted the square 67 00:04:19,150 --> 00:04:25,108 root. Of minus Seven, we do it in exactly the same way we split 68 00:04:25,108 --> 00:04:30,932 minus 7 into 7 times minus one, and we write it as the square 69 00:04:30,932 --> 00:04:35,508 root of 7 multiplied by the square root of minus one. 70 00:04:35,520 --> 00:04:38,892 Now the square root of 7. We can't simplify, will just leave 71 00:04:38,892 --> 00:04:42,826 that in this so called surd form square root of 7 and the square 72 00:04:42,826 --> 00:04:43,950 root of minus one. 73 00:04:44,500 --> 00:04:46,040 We know is I. 74 00:04:47,110 --> 00:04:50,686 So the square root of minus Seven. We can write as the 75 00:04:50,686 --> 00:04:54,262 square root of plus Seven times. I, so the introduction of this 76 00:04:54,262 --> 00:04:57,242 imaginary number I allows us to formally write down an 77 00:04:57,242 --> 00:04:59,924 expression for the square root of any negative number. 78 00:05:00,680 --> 00:05:05,036 Now using this imaginary number I, we can do various algebraic 79 00:05:05,036 --> 00:05:09,392 calculations, just as we would with normal algebra. Let me show 80 00:05:09,392 --> 00:05:12,956 you a couple of examples. Supposing were asked to 81 00:05:12,956 --> 00:05:14,144 calculate I cubed. 82 00:05:14,170 --> 00:05:18,814 Or I cubed we can write as I squared multiplied by I. 83 00:05:19,340 --> 00:05:25,976 We already know that I squared is minus one, so I squared 84 00:05:25,976 --> 00:05:29,294 becomes minus 1 multiplied by I. 85 00:05:29,310 --> 00:05:33,902 Which is just minus one times I or minus I so we can simplify 86 00:05:33,902 --> 00:05:37,838 the expression I cubed in this way just to get the answer. 87 00:05:37,838 --> 00:05:41,446 Minus I let's look at another one, supposing we have an 88 00:05:41,446 --> 00:05:45,382 expression I to the four, we could write that as I squared 89 00:05:45,382 --> 00:05:46,694 multiplied by I squared. 90 00:05:47,210 --> 00:05:51,536 And in each case I squared is minus one. So here we have minus 91 00:05:51,536 --> 00:05:55,244 1 multiplied by minus one and minus one times minus one is 92 00:05:55,244 --> 00:06:00,188 plus one. So I to the four is plus one and in the same way we 93 00:06:00,188 --> 00:06:03,278 can start to simplify any expression that involves I and 94 00:06:03,278 --> 00:06:06,892 powers of I. You'll see this imaginary number I 95 00:06:06,892 --> 00:06:09,748 in lots more calculations in the following videos.