[Script Info]
Title: 
[Events]
Format: Layer, Start, End, Style, Name, MarginL, MarginR, MarginV, Effect, Text
Dialogue: 0,0:00:00.00,0:00:00.77,Default,,0000,0000,0000,,
Dialogue: 0,0:00:00.77,0:00:03.21,Default,,0000,0000,0000,,Let's say that we have\Ntwo parallel lines.
Dialogue: 0,0:00:03.21,0:00:05.98,Default,,0000,0000,0000,,So that's one line\Nright over there,
Dialogue: 0,0:00:05.98,0:00:07.83,Default,,0000,0000,0000,,and then this is\Nthe other line that
Dialogue: 0,0:00:07.83,0:00:09.65,Default,,0000,0000,0000,,is parallel to the first one.
Dialogue: 0,0:00:09.65,0:00:11.63,Default,,0000,0000,0000,,I'll draw it as\Nparallel as I can.
Dialogue: 0,0:00:11.63,0:00:13.46,Default,,0000,0000,0000,,So these two lines are parallel.
Dialogue: 0,0:00:13.46,0:00:15.00,Default,,0000,0000,0000,,This is the symbol\Nright over here
Dialogue: 0,0:00:15.00,0:00:17.74,Default,,0000,0000,0000,,to show that these two\Nlines are parallel.
Dialogue: 0,0:00:17.74,0:00:19.92,Default,,0000,0000,0000,,And then let me draw\Na transversal here.
Dialogue: 0,0:00:19.92,0:00:21.92,Default,,0000,0000,0000,,So let me draw a transversal.
Dialogue: 0,0:00:21.92,0:00:24.63,Default,,0000,0000,0000,,This is also a line.
Dialogue: 0,0:00:24.63,0:00:29.55,Default,,0000,0000,0000,,Now, let's say that we know\Nthat this angle right over here
Dialogue: 0,0:00:29.55,0:00:32.74,Default,,0000,0000,0000,,is 110 degrees.
Dialogue: 0,0:00:32.74,0:00:36.78,Default,,0000,0000,0000,,What other angles can\Nwe figure out here?
Dialogue: 0,0:00:36.78,0:00:38.75,Default,,0000,0000,0000,,Well, the first thing\Nthat we might realize
Dialogue: 0,0:00:38.75,0:00:41.44,Default,,0000,0000,0000,,is that, look, corresponding\Nangles are equivalent.
Dialogue: 0,0:00:41.44,0:00:43.63,Default,,0000,0000,0000,,This angle, the angle\Nbetween this parallel line
Dialogue: 0,0:00:43.63,0:00:45.09,Default,,0000,0000,0000,,and the transversal,\Nis going to be
Dialogue: 0,0:00:45.09,0:00:47.37,Default,,0000,0000,0000,,the same as the angle\Nbetween this parallel line
Dialogue: 0,0:00:47.37,0:00:48.73,Default,,0000,0000,0000,,and the transversal.
Dialogue: 0,0:00:48.73,0:00:52.64,Default,,0000,0000,0000,,So this right over here is\Nalso going to be 110 degrees.
Dialogue: 0,0:00:52.64,0:00:55.66,Default,,0000,0000,0000,,Now, we also know that\Nvertical angles are equivalent.
Dialogue: 0,0:00:55.66,0:00:58.04,Default,,0000,0000,0000,,So if this is 110\Ndegrees, then this angle
Dialogue: 0,0:00:58.04,0:01:00.58,Default,,0000,0000,0000,,right over here on the opposite\Nside of the intersection
Dialogue: 0,0:01:00.58,0:01:02.68,Default,,0000,0000,0000,,is also going to be 110 degrees.
Dialogue: 0,0:01:02.68,0:01:04.68,Default,,0000,0000,0000,,And we could use that\Nsame logic right over here
Dialogue: 0,0:01:04.68,0:01:06.34,Default,,0000,0000,0000,,to say that if this\Nis 110 degrees,
Dialogue: 0,0:01:06.34,0:01:08.58,Default,,0000,0000,0000,,then this is also 110 degrees.
Dialogue: 0,0:01:08.58,0:01:09.95,Default,,0000,0000,0000,,We could've also\Nsaid that, look,
Dialogue: 0,0:01:09.95,0:01:12.91,Default,,0000,0000,0000,,this angle right over here\Ncorresponds to this angle
Dialogue: 0,0:01:12.91,0:01:16.92,Default,,0000,0000,0000,,right over here so that they\Nalso will have to be the same.
Dialogue: 0,0:01:16.92,0:01:19.36,Default,,0000,0000,0000,,Now, what about\Nthese other angles?
Dialogue: 0,0:01:19.36,0:01:23.19,Default,,0000,0000,0000,,So this angle right over\Nhere, its outside ray,
Dialogue: 0,0:01:23.19,0:01:25.28,Default,,0000,0000,0000,,I guess you could\Nsay, forms a line
Dialogue: 0,0:01:25.28,0:01:26.61,Default,,0000,0000,0000,,with this angle right over here.
Dialogue: 0,0:01:26.61,0:01:31.11,Default,,0000,0000,0000,,This pink angle is supplementary\Nto this 110 degree angle.
Dialogue: 0,0:01:31.11,0:01:35.58,Default,,0000,0000,0000,,So this pink angle plus 110\Nis going to be equal to 180.
Dialogue: 0,0:01:35.58,0:01:39.99,Default,,0000,0000,0000,,Or we know that this pink angle\Nis going to be 70 degrees.
Dialogue: 0,0:01:39.99,0:01:43.43,Default,,0000,0000,0000,,And then we know that it's a\Nvertical angle with this angle
Dialogue: 0,0:01:43.43,0:01:46.32,Default,,0000,0000,0000,,right over here, so\Nthis is also 70 degrees.
Dialogue: 0,0:01:46.32,0:01:50.62,Default,,0000,0000,0000,,This angle that's kind of\Nright below this parallel line
Dialogue: 0,0:01:50.62,0:01:53.91,Default,,0000,0000,0000,,with the transversal, the bottom\Nleft, I guess you could say,
Dialogue: 0,0:01:53.91,0:01:56.52,Default,,0000,0000,0000,,corresponds to this bottom\Nleft angle right over here.
Dialogue: 0,0:01:56.52,0:01:58.14,Default,,0000,0000,0000,,So this is also 70 degrees.
Dialogue: 0,0:01:58.14,0:02:00.14,Default,,0000,0000,0000,,And we could've also\Nfigured that out by saying,
Dialogue: 0,0:02:00.14,0:02:03.99,Default,,0000,0000,0000,,hey, this angle is supplementary\Nto this angle right over here.
Dialogue: 0,0:02:03.99,0:02:05.70,Default,,0000,0000,0000,,And then we could use\Nmultiple arguments.
Dialogue: 0,0:02:05.70,0:02:08.29,Default,,0000,0000,0000,,The vertical angle argument,\Nthe supplementary argument two
Dialogue: 0,0:02:08.29,0:02:11.35,Default,,0000,0000,0000,,ways, or the corresponding\Nangle argument to say that,
Dialogue: 0,0:02:11.35,0:02:15.94,Default,,0000,0000,0000,,hey, this must be\N70 degrees as well.