WEBVTT 00:00:00.000 --> 00:00:02.433 I have three word problems in this video. 00:00:02.433 --> 00:00:05.887 What I want to do in this video is not solve the word problems, 00:00:05.887 --> 00:00:10.154 but setup the equation that we could solve to get the answer to the word problem. 00:00:10.154 --> 00:00:13.597 What we are essentially going to do is setup the proportionality for the word problems. 00:00:13.597 --> 00:00:14.907 So In this 1st problem 00:00:14.907 --> 00:00:18.933 we have 9 markers cost $11.50. And then they ask: 00:00:18.933 --> 00:00:22.236 How much will 7 markers cost. 00:00:22.236 --> 00:00:31.333 Now, let's just set X to be equal to our answer, where X is equal to the cost of 7 markers. 00:00:31.333 --> 00:00:34.471 The way to solve a problem like this is to setup two 00:00:34.471 --> 00:00:36.333 ratios and set them equal to each other. 00:00:36.333 --> 00:00:38.815 So you could say that the ratio of 9 markers 00:00:38.815 --> 00:01:10.578 to the cost of 9 markers; 9/ 11.50 = 7/ X 00:01:10.578 --> 00:01:21.046 This is a completely valid proportion here. 00:01:21.046 --> 00:01:23.471 You could solve this to figure out how much those 00:01:23.471 --> 00:01:25.317 7 markers will cost. 00:01:25.317 --> 00:01:58.553 You could have 11.50/9 = X/7 .This is also a valid ratio. 00:01:58.553 --> 00:02:01.651 You could also think about ratios in other ways 00:02:01.651 --> 00:02:11.404 You could say, that the ratio of 9 markers to 7 markers, 00:02:11.404 --> 00:02:22.933 is going to be same as the ratio of their cost 00:02:22.933 --> 00:02:42.748 9/7 = 11.5/X or 7/9 = X/11.5 00:02:42.748 --> 00:02:51.061 So all of these would be valid proportion. 00:02:51.061 --> 00:02:54.933 Sp let's do this problem now. 7 aples cost $5. 00:02:54.933 --> 00:03:02.169 How much can I buy with $8. 00:03:02.169 --> 00:03:11.205 How many apples - let's call that X. We need to solve for X 00:03:11.205 --> 00:03:13.138 So we have the ratio between number 00:03:13.138 --> 00:03:34.933 of apples and cost of the apples - 7/5= X/8 00:03:34.933 --> 00:03:42.800 In this first situation the unknown was cost, in this example 00:03:42.800 --> 00:03:49.507 the unknown is number of apples.We can do all the different 00:03:49.507 --> 00:04:15.194 scenarios as above. we could say 7/X = 5/8 00:04:15.194 --> 00:04:19.174 Now lets do the last one. We have a cake recipe for 00:04:19.174 --> 00:04:32.660 5 people requires 2 eggs. How many eggs? So we want to know how many eggs? 00:04:32.660 --> 00:04:35.759 We will call how many eggs, which we 00:04:35.759 --> 00:04:45.225 need to find out as X, we can call it anything Y,A,B,C anything. 00:04:45.225 --> 00:04:56.671 So you could say the ratio of people to eggs is constant. 00:04:56.671 --> 00:05:13.400 We have 5 people for 2 eggs - 5/2 = 15/X 00:05:13.400 --> 00:05:38.867 Or you could say the ratio between 5/15 = 2/X 00:05:38.867 --> 00:05:46.933 All of these we setup the proportion and we can 00:05:46.933 --> 00:05:50.933 solve for X and get the answer.